将iphone应用程序连接到mysql数据库
我有应用程序我想连接到iphone应用程序我已经完成代码和PHP代码问题是,我总是得到不正确的密码警报视图。我AAM输入正确的用户名和密码,但再次显示了错误警报视图将iphone应用程序连接到mysql数据库
NSString *post =[NSString stringWithFormat:@"UserName=%@&UserPassword=%@",userNameTextField.text, userPasswordTextFiled.text];
NSString *hostStr = @"http://www.myurl.com/emrapp/connect.php?";
hostStr = [hostStr stringByAppendingString:post];
NSData *dataURL = [NSData dataWithContentsOfURL: [ NSURL URLWithString: hostStr ]];
NSString *serverOutput = [[NSString alloc] initWithData:dataURL encoding: NSASCIIStringEncoding];
if([serverOutput isEqualToString:@"Yes"]){
UIAlertView *alertsuccess = [[UIAlertView alloc] initWithTitle:@"Congrats" message:@"You are authorized "
delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
[alertsuccess show];
[alertsuccess release];
} else {
UIAlertView *alertsuccess = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Username or Password Incorrect"
delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil];
[alertsuccess show];
[alertsuccess release];
}
而且我的服务器端代码
<?php
$con = mysql_connect("emriphone.db.6420177.hostedresource.com","emriphone","Light12-");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("emriphone", $con);
$u=$_GET['UserName'];
$pw=$_GET['UserPassword'];
$query = sprintf("SELECT UserName,UserPassword from appUsers WHERE UserName='%s' AND UserPassword='%s'", mysql_real_escape_string($u),mysql_real_escape_string($pw));
$login=mysql_query($query,$con) or die(mysql_error());
if(mysql_num_rows($login)==1){
$row =mysql_fetch_assoc($login);
echo 'YES'; exit;
}
else{
echo'NO';exit;
}
mysql_connect($con);
?>
尝试使用下面的代码
NSString *data = [[NSString stringWithFormat:@"UserName=%@&UserPassword=%@",userNameTextField.text, userPasswordTextFiled.text];
NSData *postData = [data dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
// preaparing URL request to send data.
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
NSString *url = [NSString stringWithFormat:@"http://www.myurl.com/emrapp/connect.php?"];
[request setURL:[NSURL URLWithString:url]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];
[request setTimeoutInterval:7.0];
NSURLResponse *response;// = [[NSURLResponse alloc] init];
NSError *error;// = [[NSError alloc] init;
NSData *urlData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *str=[[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
NSLog(@"Login response:is %@",str);
对你有用吗? – Rupesh 2012-03-19 09:47:29
与第一次不工作相同 – user1263350 2012-03-19 10:00:48
NSLOg中的输出是什么? – Rupesh 2012-03-19 10:01:40
这个链接可以帮助你http://*.com/questions/2720288/how-to-connect-with-sqlite-in-iphone – 2012-03-19 07:19:09
这是我的链接亲爱的,但我有同样的问题 – user1263350 2012-03-19 07:28:11
字符串中的服务器输出我越来越是@“”;只有所以这就是为什么我认为它给错误可以帮助我在这s – user1263350 2012-03-19 07:56:49