带参数的shell脚本呈现

Question

#!/bin/bash 
#if present -a flag then print this echo 
#echo "A"; 
#if -b is present then print b 
#echo "B" 

#and if -c 10 present how can I read this value '10' ? 

以上就是我想看看我的剧本

，我希望能够象这样开始

myscript.sh -a -b -c 10 

或

myscript.sh 

或

myscript.sh -a -c 10 

或

myscript.sh -c 10 

等在shell上

Answer 1

型 '男人的getopt'，并按照指示。

Answer 2

您可能会看看getopts。

下面的例子是从http://wiki.bash-hackers.org/howto/getopts_tutorial

#!/bin/bash 

while getopts ":a" opt; do 
    case $opt in 
    a) 
     echo "-a was triggered!" >&2 
     ;; 
    \?) 
     echo "Invalid option: -$OPTARG" >&2 
     ;; 
    esac 
done 

Answer 3

使用getopts的考虑是这样的：

arg=-1 
while getopts "c:ab" optionName; do 
    case "$optionName" in 
    a) echo "-a is present";; 
    b) echo "-b is present";; 
    c) arg="$OPTARG"; echo "-c is present [$arg]";; 
    esac 
done 

Answer 4

#!/bin/bash 
for var in "[email protected]" 
do 
    echo "$var" 

http://osr600doc.sco.com/en/SHL_automate/_Passing_to_shell_script.html