如何从档案中只提取一种文件？

Question

给定一个包含10个文件的.zip或.rar文件，每个文件具有不同的扩展名。

鉴于我只想在其中的.jpg文件。

如何提取* .jpg而不必提取其他9个文件？

Answer 1

试试这个：

unzip test.zip '*.jpg' 

在文件名后的参数是要提取的文件。见man unzip Arguments section：

[file(s)] 
      An optional list of archive members to be processed, separated 
      by spaces. (VMS versions compiled with VMSCLI defined must 
      delimit files with commas instead. See -v in OPTIONS below.) 
      Regular expressions (wildcards) may be used to match multiple 
      members; see above. Again, **be sure to quote expressions that 
      would otherwise be expanded** or modified by the operating system. 

Answer 2

tar -xf test.tar --wildcards --no-anchored '*.jpg' 

Answer 3

您可以使用：

while read -r f; do 
    tar -xf "$zipFile" "$f" 
done < <(tar tf "$zipFile" | grep '\.jpg')