将列表转换为R中的数据帧
问题描述:
I have this list:
dput(data)
structure(list(open = structure(c(NA, 135.600006, 136.759995), .Dim = c(3L,
1L), .Dimnames = list(structure(c("2016-01-01", "2016-01-04",
"2016-01-05"), .Dim = c(3L, 1L)), "IBM")), high = structure(c(NA,
135.970001, 136.889999), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), low = structure(c(NA,
134.240005, 134.850006), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), close = structure(c(NA,
135.949997, 135.850006), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), volume = structure(c(NA,
5229400L, 3924800L), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), adj.close = structure(c(NA,
130.959683, 130.863362), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM"))), .Names = c("open",
"high", "low", "close", "volume", "adj.close"))
我试图将此列表转换为数据帧,以便我可以进行更多计算。将列表转换为R中的数据帧
我需要这个数据帧,看起来像这样:
Date Open High Low Close Volume
1985-01-02 3.18 3.18 3.08 3.08 1870906
我已经试过这样:
do.call(rbind, data)
无法看到列?有任何想法吗?
答
我会后作为回答我的评论:
data2 <- setNames(do.call('cbind.data.frame', data), names(data))
data2$date <- row.names(data2)
row.names(data2) <- NULL
data2 <- cbind.data.frame(date = data2$date, data2[,-7])
date open high low close volume adj.close
1 2016-01-01 NA NA NA NA NA NA
2 2016-01-04 135.60 135.97 134.24 135.95 5229400 130.9597
3 2016-01-05 136.76 136.89 134.85 135.85 3924800 130.8634
基本上,我们使用cbind.data.frame
而不是rbind
去接近我们想要的。从那里它重新组织data.frame
答
您可以使用for
循环来合并此列表。我用as.numeric
删除每个矩阵的行和col名称:
list.to.df <- structure(list(open = structure(c(NA, 135.600006, 136.759995), .Dim = c(3L,
1L), .Dimnames = list(structure(c("2016-01-01", "2016-01-04",
"2016-01-05"), .Dim = c(3L, 1L)), "IBM")), high = structure(c(NA,
135.970001, 136.889999), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), low = structure(c(NA,
134.240005, 134.850006), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), close = structure(c(NA,
135.949997, 135.850006), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), volume = structure(c(NA,
5229400L, 3924800L), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM")), adj.close = structure(c(NA,
130.959683, 130.863362), .Dim = c(3L, 1L), .Dimnames = list(structure(c("2016-01-01",
"2016-01-04", "2016-01-05"), .Dim = c(3L, 1L)), "IBM"))), .Names = c("open",
"high", "low", "close", "volume", "adj.close"))
names <- names(list.to.df)
df <- data.frame(Date=as.Date(row.names(list.to.df[[1]])))
for(i in 1:length(list.to.df)){
df[,i + 1] <- as.numeric(list.to.df[[i]])
names(df)[i + 1] <- names[i]
}
Date open high low close volume adj.close
1 2016-01-01 NA NA NA NA NA NA
2 2016-01-04 135.60 135.97 134.24 135.95 5229400 130.9597
3 2016-01-05 136.76 136.89 134.85 135.85 3924800 130.8634
'setNames(do.call( 'cbind.data.frame',数据),名(数据))'变你几乎在那里 – bouncyball
@bouncyball,我需要日期作为列,你可以将它添加到数据框? – user1471980
@jenesaisquoi这是一样好。修正名称,只用'setNames(data.frame(data),names(data))' – alistaire