如何在liferay portlet中使用ajax返回对象?
我需要在成功方法上返回一个字符串。 这是我在jsp页面中的AJAX代码。如何在liferay portlet中使用ajax返回对象?
<portlet:actionURL name="filterDocuments" var="filterDocuments">
<portlet:param name="action" value="filterDocuments"/>
</portlet:actionURL>
<script type="application/javascript">
var filterDto = {
page: 0,
tags: {},
search: null
};
$.ajax({
type: "POST",
url: "<%=filterDocuments%>",
data: filterDto,
success: function (msg) {
alert(msg);
}
});
</script>
这里是我在后端的处理程序。
@ActionMapping(params = "action=filterDocuments")
public void filterDocuments(ActionRequest actionRequest, ActionResponse actionResponse) throws IOException {
PrintWriter writer = PortalUtil.getHttpServletResponse(actionResponse).getWriter();
writer.write("text");
writer.flush();
writer.close();
}
结果它显示了警告消息中的空字符串。 如何处理它?
UPDATE 我改变控制器方法
@ResourceMapping(value = "filterDocuments")
public void filterDocuments(ActionRequest actionRequest, ActionResponse actionResponse) throws IOException {
PrintWriter writer = PortalUtil.getHttpServletResponse(actionResponse).getWriter();
writer.write("text");
writer.flush();
writer.close();
}
和URL在我的JSP是
<portlet:resourceURL var="ajaxResourceURL"/>
<script type="application/javascript">
var filterDto = {
page: 0,
tags: {},
search: null
};
$.ajax({
type: "POST",
url: "<%=ajaxResourceURL%>",
data: filterDto,
success: function (msg) {
alert(msg);
}
});
</script>
而现在它给了我一个异常
org.springframework。 web.portlet.NoHandlerFoundException:找不到处理程序门户请求:模式 '观看',相位 'RESOURCE_PHASE',参数映射[ '搜索' - >阵列[ ''], '页' - >阵列[ '0']]
全控制器类
@Controller
@RequestMapping("VIEW")
@Log4j
public class SpringMVCController extends MVCPortlet {
@RenderMapping
public String view(RenderRequest request, RenderResponse response) {
String view = PropertiesConfig.getAsString("views", request);
return view;
}
@Override
public void serveResource(ResourceRequest resourceRequest,
ResourceResponse resourceResponse)
throws IOException, PortletException {
try {
PrintWriter writer = resourceResponse.getWriter();
writer.write("text");
writer.flush();
writer.close();
CaptchaUtil.serveImage(resourceRequest, resourceResponse);
} catch (Exception e) {
log.error(e.getMessage());
}
}
@ResourceMapping(value = "action=filterDocuments")
public void filterDocuments(ActionRequest actionRequest, ActionResponse actionResponse) throws IOException {
PrintWriter writer = PortalUtil.getHttpServletResponse(actionResponse).getWriter();
writer.write("text");
writer.flush();
writer.close();
}
}
与更新的代码/是问题(一个或多个)以下:
我。您尚未根据您的portlet:actionURL
指定portlet:resourceURL
上的id
属性(具有所需的值)。将其更改为:
<portlet:resourceURL id="filterDocuments" var="filterDocuments" />
ii。映射方法在行动类签名不一样的UI的portlet:resourceURL
id属性的值,将其更改为:
@ResourceMapping("filterDocuments")
public void filterDocuments(ResourceRequest request, ResourceResponse response)
throws IOException, SystemException {
PrintWriter writer = response.getWriter();
writer.write("text");
writer.flush();
writer.close();
}
III。从操作类中删除另一个serveResource
方法,因为这仅适用于通用(默认)Portlet类型。
thanx。它有帮助。这liferay让我发疯 –
@SergShapoval,不客气,快乐编码! –
与您的代码的问题是,你调用'使用AJAX,这不是一个有效的模式actionURL'。 –
将'portlet:actionURL'改为'portlet:resourceURL'和'@ ActionMapping'改为'@ResourceMapping'。 –
[在portlet中使用json对象响应http请求]的可能重复(https://stackoverflow.com/questions/17592144/respond-to-http-request-with-json-object-in-portlet) –