Fabric.js链接/取消链接2对象
问题描述:
我有2个矩形对象,我用作背景模板。控件被禁用,它们可以被拖动到画布上。我希望他们表现得像一个群体:当他们中的一个被选中时,另一个也是如此,因此他们只能一起移动。我不想将它们分组,主要是因为在出口时,我需要删除其中的一个,并且我找不到这样做的方法......(除非有一种简单的方法来选择组中的项目,但不是组。项目()。remove()方法,无论是功能取消组合我的项目或似乎在我的导出功能正常工作)Fabric.js链接/取消链接2对象
答
var canvas = new fabric.Canvas('c');
var evented = false;
var rect1 = new fabric.Rect({
left: 50,
top: 30,
fill: 'blue',
width: 150,
height: 150,
hasBorders:false,
hasControls:false
});
var rect2 = new fabric.Rect({
left: 210,
top: 30,
fill: 'magenta',
width: 150,
height: 150,
hasBorders:false,
hasControls:false
});
canvas.add(rect1,rect2);
function rect1MouseDown(option){
this.mousesDownLeft = this.left;
this.mousesDownTop = this.top;
this.rect2Left = rect2.left;
this.rect2Top = rect2.top;
}
function rect1MouseMove(option){
rect2.left = this.rect2Left+ this.left - this.mousesDownLeft ;
rect2.top = this.rect2Top+ this.top- this.mousesDownTop;
rect2.setCoords();
}
function rect2MouseDown(option){
this.mousesDownLeft = this.left;
this.mousesDownTop = this.top;
this.rect1Left = rect1.left;
this.rect1Top = rect1.top;
}
function rect2MouseMove(option){
rect1.left = this.rect1Left+ this.left - this.mousesDownLeft ;
rect1.top = this.rect1Top+ this.top- this.mousesDownTop;
rect1.setCoords();
}
register();
function register(){
if(evented) return;
rect1.on('moving', rect1MouseMove);
rect1.on('mousedown', rect1MouseDown);
rect2.on('moving',rect2MouseMove);
rect2.on('mousedown',rect2MouseDown);
evented = true;
}
function unRegister(){
rect1.off('moving');
rect1.off('mousedown');
rect2.off('moving');
rect2.off('mousedown');
evented = false;
}
canvas {
border: blue dotted 2px;
}
<script src="https://rawgit.com/kangax/fabric.js/master/dist/fabric.min.js"></script>
<button onclick='register()'>Register Event</button>
<button onclick='unRegister()'>Unregister Event</button><br>
<canvas id="c" width="400" height="400"></canvas>
另外,您可以在移动一个设置左,上到另一个对象,所以只要你按照该位置移动一个物体设定位置休息。
完美!非常感谢! – zalemmm
不要忘了upvote和标记,如果它适合你。干杯;) – Durga