从Android API中的本地联系人应用程序启动我的应用程序23

Question

我试图将手机中的所有联系人与我的应用程序链接起来。然后从联系应用程序启动我的应用程序。在api < 23它工作正常。但在api> 23的联系人得到重复。所以让我知道任何人试过这!! !!这是我试过..！

public class ContactsSync extends AsyncTask<String, String, String> { 

    @Override 
    protected String doInBackground(String... params) { 
     String name, number, id; 
     for (int i = 0; i <=mIDs.size(); i++) { 
      //name = mNames.get(i); 
      id = mIDs.get(i); 
      number = mNumbers.get(i); 
      ContactsManager.addContact(Paymoney.this, new MyContact(id, number)); 
     } 
     return null; 
    } 

    @Override 
    protected void onPostExecute(String s) { 
     getContactDataAfter(); 
    } 
} 

公共静态无效的addContact（上下文的背景下，MyContact接触）{

ContentResolver resolver = context.getContentResolver(); 
    boolean mHasAccount = isAlreadyRegistered(resolver, contact.Id); 

    if(mHasAccount){ 
    } else { 

     ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>(); 

     // insert account name and account type 
     ops.add(ContentProviderOperation 
       .newInsert(addCallerIsSyncAdapterParameter(ContactsContract.RawContacts.CONTENT_URI, true)) 
       .withValue(ContactsContract.RawContacts.ACCOUNT_NAME, Constants.ACCOUNT_NAME) 
       .withValue(ContactsContract.RawContacts.ACCOUNT_TYPE, Constants.ACCOUNT_TYPE) 
       .withValue(ContactsContract.RawContacts.AGGREGATION_MODE, 
         ContactsContract.RawContacts.AGGREGATION_MODE_DEFAULT) 
       .build()); 

     ops.add(ContentProviderOperation 
       .newInsert(addCallerIsSyncAdapterParameter(ContactsContract.Data.CONTENT_URI, true)) 
       .withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0) 
       .withValue(ContactsContract.Data.MIMETYPE, CommonDataKinds.Phone.CONTENT_ITEM_TYPE) 
       .withValue(CommonDataKinds.Phone.NUMBER, contact.number) 
       .build()); 


     ops.add(ContentProviderOperation 
       .newInsert(addCallerIsSyncAdapterParameter(ContactsContract.Data.CONTENT_URI, true)) 
       .withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0) 
       .withValue(ContactsContract.Data.MIMETYPE, MIMETYPE) 
       .withValue(ContactsContract.Data.DATA1, 12345) 
       .withValue(ContactsContract.Data.DATA2, "user") 
       .withValue(ContactsContract.Data.DATA3, "Send Money") 
       .build()); 
      resolver.applyBatch(ContactsContract.AUTHORITY, ops); 

Answer 1

您需要明确聚集新RawContact到现有的（原始）联系人：

ops.add(ContentProviderOperation.newUpdate(AggregationExceptions.CONTENT_URI) 
    .withValue(AggregationExceptions.TYPE, AggregationExceptions.TYPE_KEEP_TOGETHER) 
    .withValue(AggregationExceptions.RAW_CONTACT_ID1, yourNewRawContactId) 
    .withValue(AggregationExceptions.RAW_CONTACT_ID2, someExistingRawContactId) 
    .build()); 

当然，您可以使用withValueBackReference在同一批次中运行此操作，同时创建新的RawContact