JPA /休眠子查询中from子句
我们使用JPA与Hibernate作为供应商, 我们有包含在子查询FROM子句联接,但我们得到以下错误的查询:JPA /休眠子查询中from子句
org.hibernate.hql.ast.QuerySyntaxException: unexpected token: (near line 1, column 75 [SELECT sd FROM com.hp.amber.datamodel.entities.analysis.SnapshotDates sd, (SELECT max(x.changeDate) maxChangeDate, x.viewId, x.state FROM com.hp.amber.datamodel.entities.analysis.SnapshotDates x WHERE x.changeDate<:date AND x.viewId in (:viewIds) AND x.state=:state GROUP BY x.viewId, x.state) sd2 WHERE sd.viewId = sd2.viewId AND sd.state = :state AND sd.changeDate = sd2.maxChangeDate]
这是查询:
SELECT sd
FROM SnapshotDates sd,
(SELECT max(x.changeDate) maxChangeDate, x.viewId, x.state
FROM SnapshotDates x
WHERE x.changeDate<:date AND x.viewId in (:viewIds) AND x.state=:state
GROUP BY x.viewId, x.state) sd2
WHERE sd.viewId = sd2.viewId
AND sd.state = :state
AND sd.changeDate = sd2.maxChangeDate
谢谢你帮
我没想到会HQL from子句
做子查询中https://docs.jboss.org/hibernate/orm/4.3/manual/en-US/html/ch16.html#queryhql-subqueries
注了一句:
Note that HQL subqueries can occur only in the select or where clauses.
我想你可以将其更改到本机查询和执行它的方式。
你的SQL是:
SELECT sd FROM SnapshotDates sd, (SELECT max(x.changeDate) maxChangeDate, x.viewId, x.state FROM SnapshotDates x WHERE x.changeDate<:date AND x.viewId in (:viewIds) AND x.state=:state GROUP BY x.viewId, x.state) sd2 WHERE sd.viewId = sd2.viewId AND sd.state = :state AND sd.changeDate = sd2.maxChangeDate
你可以重写你的SQL像
SELECT sd
FROM SnapshotDates sd,
WHERE sd.viewId in (:viewIds)
AND sd.state = :state
sd.changeDate = (SELECT max(x.changeDate) FROM SnapshotDates x WHERE x.viewId = ds.viewId AND x.state = ds.state)
查找例如
SELECT m FROM Professor m WHERE (SELECT COUNT(e) FROM Professor e WHERE e.manager = m) > 0
http://www.java2s.com/Code/Java/JPA/EJBQLWhereClauseWithSubQuery.htm
我的灵感相似例如 我有SQL
select k.* from kredits k,
(select client_id, max(r_date) r_date from kredits k group by client_id) k2
where k.client_id = k2.client_id
AND k.r_date = k2.r_date
order by k.id
改写为PQL
select k From Kredit k
where k.rDate = (select MAX(k2.rDate) from Kredit k2 where k2.clientId = k.clientId)
order by k.id
它将会被翻译成
select kredit0_.id as id28_, kredit0_.client_id as client59_28_ from kredits kredit0_
where kredit0_.r_date=(select MAX(kredit1_.r_date) from kredits kredit1_ where kredit1_.client_id=kredit0_.client_id)
order by kredit0_.id
返回相同的结果,SQL。
使用Hebirnate 3.3.1与MySQL 5.0.24