从字符串中删除的特殊字符的jQuery

Question

过滤数据我有这样的字符串：

var str = "f2025%20%3D%20%2209%3A00%22%20and%20f5118288%20%3D%20%222017-03-31%22#"; 

如何删除所有的特殊字符{ '％20％3D％20％22'， '％3A' ，'％22％20'，'％20'}返回列表值，如下所示{'f2025'，'09'，'00'，'和'，'f5118288'，'2017-03-31 “}

Answer 1

您可以使用以下正则表达式来分割使用此字符串

%20%3D%20%22|%3A|%22%20|%20|%22# 

var str = "f2025%20%3D%20%2209%3A00%22%20and%20f5118288%20%3D%20%222017-03-31%22#"; 
var strArray = str.split(/%20%3D%20%22|%3A|%22%20|%20|%22#/) 

Answer 2

您可以使用replace特殊字符和split的欲望的结果。

var str = "f2025%20%3D%20%2209%3A00%22%20and%20f5118288%20%3D%20%222017-03-31%22#"; 
 
str = str.replace(/%20%3D%20%22/g, "@").replace(/%3D/g, "").replace(/%3A/g, "@").replace(/%22%20/g, "@").replace(/#/g, "").replace(/%20/g, "@").replace(/%22/g, "@"); 
 
var Result = str.split('@'); 
 
alert(Result);

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