解析错误：语法错误，意外'（T_ENCAPSED_AND_WHITESPACE），预计标识符（T_STRING）或可变

问题描述：

当我做这个，我不断收到此错误：解析错误：语法错误，意外'（T_ENCAPSED_AND_WHITESPACE），预计标识符（T_STRING）或可变

<?php 
$info = $_POST['mname']; 
$info = ucwords($info); 

// Make a MySQL Connection 
mysql_connect("localhost", "user", "password") or die(mysql_error()); 
mysql_select_db("javadatest") or die(mysql_error()); 

// Get a specific result from the "example" table 
$result = mysql_query("SELECT * FROM movieList 
WHERE name = '$info'") or die(mysql_error()); 

// get the first (and hopefully only) entry from the result 
$row = mysql_fetch_array($result); 
// Print out the contents of each row into a table 
//echo $row['name']." ".$row['year']." ".$row['genre']; 
echo " 
    <script language=javascript> 
    var jsvar; 
    jsvar = <?php echo $row['name'], $row['year'], $row['genre'];?> 
    function buy() { 
    window.location = \"https://www.paypal.com\"; 
    alert(\"Thanks for shopping at Movie Store\");  
    } 
    var myWindow = window.open('', '', 'width = 300, height = 300); 
    myWindow.document.write(jsvar); 
    myWindow.document.write('<body>'); 

    myWindow.document.write('<input type="button" value="Buy" onclick=/"buy()/">'); 

    myWindow.document.write('</body>'); 

//myWindow.buy = buy; 
</script> 
"; 
?>

我想在PHP中使用JavaScript通过将我的JavaScript代码放入我的echo语句中。我无法弄清楚我做错了什么。任何帮助，将不胜感激。

'$ _POST ['mname'] =“或1 = 1”'。繁荣！ – elclanrs 2013-04-10 03:47:50

我喜欢类似问题的代表点 – zerkms 2013-04-10 03:49:14

@elclanrs现在他们可以看到所有的电影xD – Musa 2013-04-10 03:54:04

答

你并不需要在此线

jsvar = <?php echo $row['name'], $row['year'], $row['genre'];?>

只使用

jsvar = {$row['name']} {$row['year']} {$row['genre']};

，因为你已经在PHP。

而且

更换

myWindow.document.write('<input type="button" value="Buy" onclick=/"buy()/">');

与

myWindow.document.write('<input type=\"button\" value=\"Buy\" onclick=\"buy()\">');

我很确定无论'jsvar = {$ row ['name']} {$ row ['year']} {$ row ['genre']};'会导致一个js错误。 – Musa 2013-04-10 03:53:15

答

myWindow.document.write('<input type="button" value="Buy" onclick=/"buy()/">');

应该

myWindow.document.write(\"<input type='button' value='Buy' onclick='buy()'>\");

并参阅下面的@Dipesh Parmar的答案 – 2013-04-10 03:49:51

答

$row = mysql_fetch_array($result); 
    // Print out the contents of each row into a table 
    //echo $row['name']." ".$row['year']." ".$row['genre']; 
    ?> 
     <script language=javascript> 
     var jsvar; 
     jsvar = <?php echo json_encode($row['name']), json_encode($row['year']), json_encode($row['genre']);?> 
     function buy() { 
     window.location = \"https://www.paypal.com\"; 
     alert(\"Thanks for shopping at Movie Store\");  
     } 
... 
</script>

解析错误：语法错误，意外'（T_ENCAPSED_AND_WHITESPACE），预计标识符（T_STRING）或可变

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