PHP的MySQL数据库连接错误
问题描述:
我有以下的PHP代码从HTML表单获取用户的登录信息:PHP的MySQL数据库连接错误
$con=mysqli_connect("host","user","pass","db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "select username from users where user='$_POST[username]' limit1";
$result = mysql_query($query);
echo result;
但是当我运行它,我似乎得到这些错误:
警告:请求mysql_query()[function.mysql查询]:无法通过插座连接到本地 MySQL服务器 '/目录省略'(2)在 /目录省略第10行
警告:MYS ql_query()[function.mysql查询]:服务器 的链接不能建立在 /目录下省略线10
任何人都可以请大家帮帮忙?非常感谢!
答
您有混合mysqli
与mysql
所以有一个错别字很多
代码应该是:
$con = mysqli_connect("host","user","pass","db");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$u = $_POST['username'];
$sql = "SELECT username FROM users WHERE user='$u' LIMIT 1";
$query = mysqli_query($con, $sql);
if ($row = mysqli_fetch_assoc($query)) {
echo $row['username'];
}
希望它的工作。
,或者您需要打印的所有行应该是:
while ($row = mysqli_fetch_assoc($query)) {
echo $row['username'];
}
+0
非常感谢你! – user1049712
+0
完全没问题。 :-) –
答
$query = "select username from users where user='$_POST[username]' limit1";
$result = mysql_query($query);
这些行应该像下面
$query = "SELECT username FROM users WHERE user='".$_POST['username']."' LIMIT 0,1";
$result = mysqli_query($con,$query);
print_r(mysqli_fetch_array($result));
你混合'mysql_ *'和'mysqli_ *' –