从数据库读取时遇到问题
问题描述:
我正在编写一个任务,我需要弄清楚如何读取使用已编码的PHP脚本创建的数据库文件。我是Android平台的新手,在接下来的一周教程中花了几个小时,但仍然很挣扎。我需要从数据库中读取并在屏幕上的UI中显示。我确信它不会太困难,但我正在某处滑倒!任何帮助将被真正赞赏。从数据库读取时遇到问题
当前PHP脚本 -
<html>
<body>
<?php
//Connect to college database
$studentnum = "SY090627";
$con = mysql_connect("localhost","******","*******");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("computin_mobile", $con);
//Select all needed student data
//Must include custext from student table to retrive students college username
$result = mysql_query("SELECT * FROM students, time WHERE (time.CusText5='$studentnum' AND students.StuRef ='$studentnum') ORDER BY time.DayNum ASC, time.StartTime");
$newLine = "\n";
try
{
//create the database
$database = new SQLiteDatabase('myDatabase.sqlite', 0666, $error);
}
catch(Exception $e)
{
die($error);
}
//add Lesson table to database
$query = 'CREATE TABLE Lessons ' .
'(Day TEXT, StartTime TEXT, EndTime TEXT, Teacher TEXT, Description TEXT, Room TEXT)';
if(!$database->queryExec($query, $error))
{
die($error);
}
while($row = mysql_fetch_array($result))
{
//insert data into database
$dayr = $row['Day'];
$query =
'INSERT INTO Lessons (Day, StartTime, EndTime, Teacher, Description, Room) ' .
'VALUES ("'.$row['Day'].'", "'.$row['StartTime'].'", "'.$row['EndTime'].'", "'.$row['Teacher'].'", "'.$row['Description'].'", "'.$row['Room'].'")';
if(!$database->queryExec($query, $error))
{
die($error);
}
}
//read data from database
$query = "SELECT * FROM Lessons";
if($result = $database->query($query, SQLITE_BOTH, $error))
{
while($row = $result->fetch())
{
print("Day: {$row['Day']} <br />" .
"Start Time: {$row['StartTime']} <br />".
"End Time: {$row['EndTime']} <br />".
"Teacher: {$row['Teacher']} <br />".
"Description {$row['Description']} <br />".
"Room: {$row['Room']} <br /><br />");
}
}
else
{
die($error);
}
?>
</body>
</html>
@Nick:我希望,你创造了使用PHP网页和instered该数据在MySQL使用PHP,你的需要是你想要显示在Android的网页,如果你修改了那些在UI和UI,这些修改,必须存储在MySQL数据库,我是吗???,这是你的需要?? ?? – 2011-01-10 14:26:45