是否有可能在非web应用程序中使用togglz

Question

我正试图查找是否可以在非web应用程序中使用togglz - 就像我们有普通的java项目或java批处理程序一样。

我尝试在独立应用程序中添加togglz库并尝试运行它。

这是我的代码片段 -

import com.feature.MyFeature; 

public class Test { 

    public static void main(String[] args) { 

     Test t = new Test(); 
     boolean valid=t.validate("CREATE_TEAM"); 
     System.out.println(valid); 

    } 

    public boolean validate(String feature){ 

     if (MyFeature.valueOf(feature).isActive()) { 
     return true; 
     } 

     return false; 
    } 

} 

它说 -

Exception in thread "main" java.lang.IllegalStateException: Could not find the FeatureManager. For web applications please verify that the TogglzFilter starts up correctly. In other deployment scenarios you will typically have to implement a FeatureManagerProvider as described in the 'Advanced Configuration' chapter of the documentation. 
    at com.amdocs.switchlite.core.context.FeatureContext.getFeatureManager(FeatureContext.java:53) 
    at com.feature.MyFeature.isActive(MyFeature.java:20) 
    at Test.validate(Test.java:22) 
    at Test.main(Test.java:12) 

Answer 1

您必须正确配置Togglz，使其工作。在独立应用程序中，我推荐以下设置。

首先使用FeatureManagerBuilder创建一个FeatureManager。事情是这样的：

FeatureManager featureManager = FeatureManagerBuilder.begin() 
     .featureEnum(Features.class) 
     .stateRepository(new InMemoryStateRepository()) 
     .userProvider(new NoOpUserProvider()) 
     .build(); 

的告诉StaticFeatureManagerProvider关于你的经理：

StaticFeatureManagerProvider.setFeatureManager(featureManager); 

现在StaticFeatureManagerProvider能够告诉Togglz你FeatureManager，一切都应该正常工作！

Features.FOOBAR.isActive(); 
// > false