如何使用搜索按钮访问来自大型JSON文件的特定数据?
问题描述:
我的最终目标是使用d3
,在那里我有ui-widget
一个类似的搜索创建强制布局:如何使用搜索按钮访问来自大型JSON文件的特定数据?
<div class="ui-widget">
<input id="search">
<button type="button" onclick="searchNode()">Search</button>
</div>
我想使用ui-widget
搜索节点,当它发现它,我想只显示包含所有链接和节点的节点。 问题是,我在链接的大JSON文件中有多组节点和链接。我不知道我应该如何加载所有这些。这里有一些我想到的选项:
- 用键/值 - >名称/ JSON的所有内容创建一个hashmap,并将其推入一个数组中。当我使用该搜索按钮进行搜索时,我将只看该键并显示该值。
- 重新格式化JSON以拥有所有节点和所有链接后,在2个大块中,不像我现在拥有节点/链接,节点,链接。
我有包含许多JSON的
JSON.json
{
"nodes": [
{"id": "Source","label":"source","group": 0},
{"id": "Parent_1","label":"name6","group": 1},
{"id": "Parent_2","label":"name5","group": 1},
{"id": "Parent_3","label":"name4","group": 1},
{"id": "Child_1","label":"name3","group": 2},
{"id": "Child_2","label":"name2","group": 2},
{"id": "Child_3","label":"name1","group": 2},
{"id": "Child_4","label":"name0", "group": 3}
],
"links": [
{ "source": "Source","target": "Parent_1"},
{ "source": "Source","target": "Parent_2"},
{ "source": "Source","target": "Parent_3"},
{ "source": "Source","target": "Child_1"},
{ "source": "Source","target": "Child_2"},
{ "source": "Source","target": "Child_3"},
{ "source": "Child_2","target": "Child_4"}
]
}
{
"nodes": [
{"id": "Source","label":"source","group": 0},
{"id": "Parent_12","label":"name6","group": 1},
{"id": "Parent_22","label":"name5","group": 1},
{"id": "Parent_32","label":"name4","group": 1},
{"id": "Child_12","label":"name3","group": 2},
{"id": "Child_22","label":"name2","group": 2},
{"id": "Child_32","label":"name1","group": 2},
{"id": "Child_42","label":"name0", "group": 3}
],
"links": [
{ "source": "Source","target": "Parent_12"},
{ "source": "Source","target": "Parent_22"},
{ "source": "Source","target": "Parent_32"},
{ "source": "Source","target": "Child_12"},
{ "source": "Source","target": "Child_22"},
{ "source": "Source","target": "Child_32"},
{ "source": "Child_22","target": "Child_42"}
]
}
的Index.html
<!DOCTYPE html>
<meta charset="utf-8">
<style>
.links line {
stroke: #999;
stroke-opacity: 0.6;
}
.nodes circle {
stroke: #fff;
stroke-width: 1.5px;
}
.node text {
font: 9px helvetica;
}
</style>
<svg width="960" height="600"></svg>
<script src="https://d3js.org/d3.v4.min.js"></script>
<script>
var svg = d3.select("svg"),
width = +svg.attr("width"),
height = +svg.attr("height");
var color = d3.scaleOrdinal(d3.schemeCategory20);
var simulation = d3.forceSimulation()
.force("link", d3.forceLink().id(function(d) { return d.id; }))
.force("charge", d3.forceManyBody())
.force("center", d3.forceCenter(width/2, height/2));
d3.json("JSON.json", function(error, graph) {
if (error) throw error;
var link = svg.append("g")
.attr("class", "links")
.selectAll("line")
.data(graph.links)
.enter().append("line")
.attr("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = svg.append("g")
.attr("class", "nodes")
.selectAll("circle")
.data(graph.nodes)
.enter().append("circle")
.attr("r", 5)
.attr("fill", function(d) { return color(d.group); })
.call(d3.drag()
.on("start", dragstarted)
.on("drag", dragged)
.on("end", dragended));
node.append("text")
.attr("dx", 10)
.attr("dy", ".35em")
.text(function(d) { return d.label })
.style("stroke", "gray");
node.on("click", function() {
alert(function(d){return d.Statement})
d3.event.stopPropagation();
});
node.on('mouseover', function(d){
var nodeSelection = d3.select(this).style({opacity:'0.8'});
nodeSelection.select("text").style({opacity:'1.0'});
})
simulation
.nodes(graph.nodes)
.on("tick", ticked);
simulation.force("link")
.links(graph.links);
function ticked() {
link
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node
.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
}
});
function dragstarted(d) {
if (!d3.event.active) simulation.alphaTarget(0.3).restart();
d.fx = d.x;
d.fy = d.y;
}
function dragged(d) {
d.fx = d3.event.x;
d.fy = d3.event.y;
}
function dragended(d) {
if (!d3.event.active) simulation.alphaTarget(0);
d.fx = null;
d.fy = null;
}
</script>
我想要的是类似这样的这个大JSON,除了我所有的节点都保存在不同的文件中:http://jsfiddle.net/simonraper/Bf5nM/?utm_source=website&utm_medium=embed&utm_campaign=Bf5nM
如果问题不清楚,请告诉我,以便我可以编辑,谢谢。
我解析了多个文件,结果是一个大的JSON文件。在这个JSON文件中,我可以看到一组节点和链接,并且我想一次代表一个组。
答
如果您想单独搜索它们,则不需要将它们全部放入一个数组中。我对d3不熟悉,但不会像这样做一个简单的循环做伎俩;其中currentObject
是你想搜索的JSON块:
var searchedId = document.getElementById("search").value;
for (var i=0; i<currentObject.nodes.length; i++) {
var node = currentObject.nodes[i];
if (node.id == searchedId) {
// display node
}
}
你在寻找什么?该ID,标签或组? – clabe45
@ clabe45我通过id搜索,与标签的id可以是相同的并不重要 –
您能详细说明吗?你有多个json文件? – clabe45