检查所有鼠标按钮的按钮状态

Question

有没有更好的方法来检查所有鼠标按钮的按钮状态，而不是检查任何不同的按钮多余？

var mouseEventArgs = (System.Windows.Input.MouseEventArgs)e.StagingItem.Input; 

if (mouseEventArgs.LeftButton == MouseButtonState.Released && 
    mouseEventArgs.MiddleButton == MouseButtonState.Released && 
    mouseEventArgs.RightButton == MouseButtonState.Released && 
    mouseEventArgs.XButton1 == MouseButtonState.Released && 
    mouseEventArgs.XButton2 == MouseButtonState.Released) 
{ 
    return; 
} 

如果不是，我怎么能做得更优雅，不用重复自己这么多？

在此先感谢！

Answer 1

我不认为有很多你可以做，除了重构这个方法，因为没有为所有按钮预定义的集合。如果你想让它完全淡出人们的视线，你可以使用扩展方法是这样的：

public static class Extensions 
{ 
    public static bool CheckUniformButtonState(this MouseButtonEventArgs e, MouseButtonState state) 
    { 
     switch (state) 
     { 
      case MouseButtonState.Pressed: 
       return (e.LeftButton == MouseButtonState.Pressed && 
        e.RightButton == MouseButtonState.Pressed && 
        e.MiddleButton == MouseButtonState.Pressed && 
        e.XButton1 == MouseButtonState.Pressed && 
        e.XButton2 == MouseButtonState.Pressed); 
      case MouseButtonState.Released: 
       return (e.LeftButton == MouseButtonState.Released && 
        e.RightButton == MouseButtonState.Released && 
        e.MiddleButton == MouseButtonState.Released && 
        e.XButton1 == MouseButtonState.Released && 
        e.XButton2 == MouseButtonState.Released); 
      default: 
       return false; 
     } 
    } 
} 

（不是每个人在没有检查是否按下所有的5个按钮。）

然后你就可以检查这样的：

if (mouseEventArgs.CheckUniformButtonState(MouseButtonState.Released)) 
{ 
    return; 
} 

Answer 2

var buttonStates = new [] { 
    mouseEventArgs.LeftButton, 
    mouseEventArgs.MiddleButton, 
    mouseEventArgs.RightButton, 
    mouseEventArgs.XButton1, 
    mouseEventArgs.XButton2}; 

if (buttonStates.All(s => s == MouseButtonState.Released)) 
{ 
    return; 
}