如何在android中播放youtube视频?
我使用下面的类来播放YouTube视频:
http://keyeslabs.com/joomla/samplecode/introvideoactivity/IntroVideoActivity.java如何在android中播放youtube视频?
main Activity contain code:
Intent lVideoIntent = new Intent(null, Uri.parse("ytv:jRB8dQ5kiLg"), youtube1.this, IntroVideoActivity.class);
startActivity(lVideoIntent);
它加载视频,但经过一段时间后给出了一个错误“抱歉,该视频无法播放”
并在日志中给出如下的错误。
-> http://www.youtube.com/get_video?video_id=jRB8dQ5kiLg&t=vjVQa1PpcFPMdWwPOC2JchyOxvrnNsRs1UyVc7gGd5I%3D&fmt=18
-> ERROR/HTTPDataSource(34): HTTP request failed w/ http status 404
-> INFO/AwesomePlayer(34): mConnectingDataSource->connect() returned -1004
-> ERROR/MediaPlayer(541): error (1, -1004)
我不明白我的错误在哪里。谁能帮我?
HTTP request failed w/ http status 404
是一个页面未找到错误,所以我会建议网址是错误的。我尝试了错误中的链接,它是一个空白页面。
感谢您的回放。我尝试了下面的链接,但这不适合我。给出错误抱歉,此视频无法播放........ http://www.youtube.com/v/jRB8dQ5kiLg – 2011-05-10 12:27:10
如果您发现我的答案正确或有用,请接受它或投票它。 – techiServices 2011-05-10 14:23:28
使用嵌入式链接我可以播放youtube视频。
Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.youtube.com/embed/"+sn+"?autoplay=1"));
startActivityForResult(i, 0);
尝试这样:
public class MainActivity extends Activity {
VideoView mVideoView;
ProgressBar mProgressBar;
ProgressDialog mProgressDialog;
String url, videoUrl;
Uri rstlUrl;
String[] urlRstp;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mVideoView=(VideoView)findViewById(R.id.videoView);
mProgressBar=(ProgressBar)findViewById(R.id.progressBarV);
videoUrl=getIntent().getExtras().getString("urla");
//from other activity here... videoUrl is sth like : http://www.youtube.com/watch?v=ER9vmhxFucg
new MyTask().execute();
}
public class MyTask extends AsyncTask<Void, Void, Void>
{
@Override
protected void onPreExecute() {
super.onPreExecute();
mProgressBar.setVisibility(LinearLayout.VISIBLE);
}
@Override
protected Void doInBackground(Void... params) {
url=getUrlVideoRTSP(videoUrl);
rstlUrl=Uri.parse(url);
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
mVideoView.setVideoURI(rstlUrl);
MediaController mc = new MediaController(VODVideoPlayActivity.this);
mVideoView.setMediaController(mc);
mVideoView.requestFocus();
mVideoView.start();
mc.show();
mProgressBar.setVisibility(LinearLayout.GONE);
}
}
public static String getUrlVideoRTSP(String urlYoutube)
{
try
{
String gdy = "http://gdata.youtube.com/feeds/api/videos/";
DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
String id = extractYoutubeId(urlYoutube);
URL url = new URL(gdy + id);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
Document doc = documentBuilder.parse(connection.getInputStream());
Element el = doc.getDocumentElement();
NodeList list = el.getElementsByTagName("media:content");///media:content
String cursor = urlYoutube;
for (int i = 0; i < list.getLength(); i++)
{
Node node = list.item(i);
if (node != null)
{
NamedNodeMap nodeMap = node.getAttributes();
HashMap<String, String> maps = new HashMap<String, String>();
for (int j = 0; j < nodeMap.getLength(); j++)
{
Attr att = (Attr) nodeMap.item(j);
maps.put(att.getName(), att.getValue());
}
if (maps.containsKey("yt:format"))
{
String f = maps.get("yt:format");
if (maps.containsKey("url"))
{
cursor = maps.get("url");
}
if (f.equals("1"))
return cursor;
}
}
}
return cursor;
}
catch (Exception ex)
{
Log.e("Get Url Video RTSP Exception======>>", ex.toString());
}
return urlYoutube;
}
protected static String extractYoutubeId(String url) throws MalformedURLException
{
String id = null;
try
{
String query = new URL(url).getQuery();
if (query != null)
{
String[] param = query.split("&");
for (String row : param)
{
String[] param1 = row.split("=");
if (param1[0].equals("v"))
{
id = param1[1];
}
}
}
else
{
if (url.contains("embed"))
{
id = url.substring(url.lastIndexOf("/") + 1);
}
}
}
catch (Exception ex)
{
Log.e("Exception", ex.toString());
}
return id;
}
你为什么不只是使用: startActivity(新意图(Intent.ACTION_VIEW,Uri.parse())) ; 而不是第三方代码? – TofferJ 2011-05-06 14:42:38
好主意@TofferJ,但我认为图书馆正在使用,因此视频在应用内播放 - 不会在单独的YouTube应用中播放。 – 2011-05-06 14:46:24
您确定YouTube网址正确吗? HTTP 404错误意味着无法找到URL - “找不到页面”错误。这正是我尝试使用该URL时所得到的结果。也许该库所生成的URL不再是YouTube使用的API?我会检查YouTube API文档以确保正确生成URL。 – 2011-05-06 14:49:25