TSQL - 聚合函数表达式上含集合错误
您好我有一个过程,像这样:TSQL - 聚合函数表达式上含集合错误
CREATE PROCEDURE dbo.DWS_PROG (
@fromDate datetime = '2012-01-01',
@maxMoney money = 200,
@limit int = 200
)
AS
SET NOCOUNT ON;
SELECT TOP (@limit)
convert(int,P.P_ID) AS 'ID'
, max(convert(MONEY,isnull(P.NGp,P.NGz))) AS 'NG'
, max(convert(MONEY,(CASE WHEN D.Doc_Type = 0x0000000000000016
THEN Cash_PLN
ELSE 0 END))) AS 'Interests'
, (SELECT TOP 1 convert(VARCHAR, H.Data_zmiany,105)
FROM dbo.Pozew_Historia_Stanow H
WHERE H.P_ID = P.P_ID
AND H.Stan_nastepny_id = 0x000000000000000D /*PZ*/) AS 'Data Pozwu'
, max((CASE WHEN Sad_Id=0x0000000000000E08
THEN 'EL'
ELSE 'PA' END)) AS 'TYPE'
, max((CASE WHEN Cost_Name =0x0000000000000008
THEN convert(varchar, Pay_Date,105)
ELSE NULL END)) AS 'Data pierwszego kosztu wpisu sądowego'
, (SELECT TOP 1 convert(VARCHAR, H.Data_zmiany,105)
FROM dbo.Pozew_Historia_Stanow H
WHERE H.P_ID = P.P_ID
AND H.Stan_nastepny_id = 0x00000000000000DD /*EGZ-1*/) AS 'Data wszczęcia egzekucji'
, sum((CASE WHEN D.Doc_Type = 0x0000000000000003
AND D.Pay_Date >= @fromDate
AND D.Pay_Date < DATEADD(mm,DATEDIFF(mm,0,@fromDate) + 1,0)
THEN Cash_PLN
ELSE 0 END)) AS 'M0'
FROM dbo.Pozew P
JOIN dbo.Orders Z
ON Z.Orders_Id = P.Orders_Id
JOIN dbo.Docs D
ON D.P_ID = P.P_ID
WHERE ((P.NGp IS NOT NULL AND P.NGp < @maxMoney) OR (P.NGp IS NULL AND P.NGz < @maxMoney))
AND P.Stan IN ('PZ-PORAŻKA','PZ-PORAŻ-UB','PZ-PSPPOR-SP','PZ-PSPPOR-UP','PZ-PSSSUK-UP','PZ-ZAPŁATA','EGZ-C-ROSZ-1','EGZ-C-ROSZ-2','EGZ-SUKCES-S','EGZ-ZAS-R','EGZ-NZAS-R','EGZ-BS-1C','EGZ-WSZP-1','EGZ-WSZP-2','EGZ-SPL')
AND (SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
ORDER BY dbo.Docs.Pay_Date) >= @fromDate
GROUP BY P.P_ID
这basicly工作正常,但我有一个错误。 在JOIN之前的最后一行中,我为所有类型为0x00 ... 03的文档和Pay_date介于@param和param之间的月末之间进行结算。简单和工程:)
但我必须与子查询替换@fromDate:
SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date
所以,对于每一个文件的查询会第一时间与日期特定类型的付款,然后将总结从开始的所有款项这个日期到月底。
SUM应该是这样的:
SUM((CASE WHEN D.Doc_Type = 0x0000000000000003
AND D.Pay_Date >=
(SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date)
AND D.Pay_Date < DATEADD(mm, DATEDIFF(mm, 0,
(SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date)) + 1,0)
THEN Cash_PLN
ELSE 0 END)) AS 'M0'
但这样做Management Studio中抛出一个错误后:
Cannot perform an aggregate function on an expression containing an aggregate or a subquery.
我试图解决近2天。 任何想法?
对不起,不显示表的结构,但数据库是太大了,我只需要一种方法来解决这个错误:)
我的表看起来像这样: 表Pozew:ID,姓名等
表文档:文档ID,p_id的(从Pozew表键),DOC_TYPE,cost_name,pay_date,cash_PLN
而且样本记录看起来像这样:
文档:
1,1,15,8,'2011-02-04',400
1,1,3,5,'2011-02-09',0
1,1,3,5,'2011 -02-12' ,0
1,1,3,5, '2011-02-04',0
简单的场景: 我们添加一条记录到文件表说,我们有cost_name 1号文件= 0x8,则添加其他文档,但Doc_Type = 0x3。
所以我们想要得到所有具有doc_Type = 0x3的文档,并且在cost_name = 0x8的第一个文档的创建日期和月末之间添加。 但是我们必须将他们分组为每个Pozew_id。
对不起,我倒英语:/
我创建了一个简单的查询,将更加清楚地显示我的问题:
DECLARE @fromDate varchar
SET @fromDate = '2011-06-01'
SELECT TOP 100
sum((CASE WHEN D.Typ_dokumentu = 0x0000000000000003
AND D.Data_platnosci >=
(SELECT TOP 1 Data_platnosci
FROM Dokumenty
WHERE Pozew_Id = P.Pozew_Id
AND Nazwa_kosztu = 0x0000000000000008
AND Data_platnosci >= @fromDate
GROUP BY Pozew_Id)
AND Data_platnosci < DATEADD(mm,DATEDIFF(mm,0,
(SELECT TOP 1 Data_platnosci
FROM Dokumenty
WHERE Pozew_Id = P.Pozew_Id
AND Nazwa_kosztu = 0x0000000000000008
AND Data_platnosci >= @fromDate
GROUP BY Pozew_Id)
) + 1,0) THEN Kwota_PLN ELSE 0 END)) AS 'M0'
FROM
Dokumenty D
JOIN Pozew P
ON D.Pozew_Id = P.Pozew_Id
WHERE
((P.NGp IS NOT NULL
AND
P.NGp < 200)
OR
(P.NGp IS NULL
AND
P.NGz < 200))
AND
P.Stan IN ('PZ-PORAŻKA','PZ-PORAŻ-UB','PZ-PSPPOR-SP')
AND
(SELECT TOP 1
dbo.Dokumenty.Data_platnosci
FROM
dbo.Dokumenty
WHERE
dbo.Dokumenty.Pozew_Id = P.Pozew_Id
AND
dbo.Dokumenty.Nazwa_kosztu = 0x0000000000000008
ORDER BY
dbo.Dokumenty.Data_platnosci) >= @fromDate
岂不是可能有一个派生表在你的加盟商提供“第一每种类型的支付@fromDate后”,然后在你的选择声明与此相比较。
即衍生查询类似
select p_id, min(pay_date) startDate
from docs
where cost_name = 0x0000000000000008
and pay_date >= @fromDate
group by p_id
order by pay_date
您按付款从而获得相应的起始日期的加盟派生表。
那么你的总和:
sum((case when d.doc_type = 0x0000000000000003
and d.pay_date >= startDate
and month(d.pay_date) = month(startDate)
and year(d.pay_date) = year(startDate)) then cash_pln
else 0 end) as 'M0'
注意我没有尝试这样做,因此它可能不会是完全正确的,但希望它显示的原则
我会把pay_date到一个变量,并与工作。毕竟这是一个不变的价值。
DECLARE @pay_date datetime
SET @pay_date = (SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date)
然后在查询
AND D.Pay_Date >= @pay_date
感谢您的回答,但是(抱歉,如果这听起来很愚蠢)如果我声明了一个变量并如上使用它,我将使用pay_date大于@pay_date的所有记录。我需要做的是为每个文档选择pay_date。我将编辑我的帖子,以显示我想完成什么样的逻辑:) – Misiu 2012-02-28 10:04:28
对不起@Filip德沃思与格式混乱:/ – Misiu 2012-02-28 09:55:17
不用担心。在vg中gg = G。 – 2012-02-28 09:58:15