哈希表ConvertTo-Json PowerShell格式问题

Question

我在PowerShell中使用哈希表来获取数据并将其转换为JSON。我是PS新手，因此无法验证JSON。这里是我的代码：

################## intro 
$userIntro = @{} 
function getIntro { 
    $userIntro.Add("first_name", "John") 
    $userIntro.Add("last_name", "Smith") 
    $userIntro.Add("age", "28") 
} 
getIntro 
$userIntro | ConvertTo-Json 

################## address 
$address = @{} 
function getAddress { 
    $address.Add("street", "21 2nd St") 
    $address.Add("city", "New York") 
    $address.Add("state", "NY") 
    $address.Add("zipcode", 12345) 
} 
getAddress 
$address | ConvertTo-Json 

出把代码是这样的：

{ 
    "last_name": "Smith", 
    "age": "28", 
    "first_name": "John" 
} 
{ 
    "street": "21 2nd St", 
    "state": "NY", 
    "zipcode": 12345, 
    "city": "New York" 
} 

正如你所看到的，这不是有效的JSON语法，因为我将两个不同的对象和它的相应的输出。

但是，我真正想要实现的是以下内容......如何将对象合并为一个转换？并最好添加分解到这样的水平。

{ 
    "userIntro": { 
     "last_name": "Smith", 
     "age": "28", 
     "first_name": "John" 
    }, 
    "address": { 
     "street": "21 2nd St", 
     "state": "NY", 
     "zipcode": 12345, 
     "city": "New York" 
    } 
} 

Answer 1

我想你只需要结合$address和$userIntro，然后将其转换成JSON哈希表：

################## intro 
$userIntro = @{} 
function getIntro { 
    $userIntro.Add("first_name", "John") 
    $userIntro.Add("last_name", "Smith") 
    $userIntro.Add("age", "28") 
} 
getIntro 
#$userIntro | ConvertTo-Json 

################## address 
$address = @{} 
function getAddress { 
    $address.Add("street", "21 2nd St") 
    $address.Add("city", "New York") 
    $address.Add("state", "NY") 
    $address.Add("zipcode", 12345) 
} 
getAddress 
#$address | ConvertTo-Json 

$combined = @{} 
$combined.Add("userIntro", $userIntro) 
$combined.Add("address", $address) 
$combined | ConvertTo-Json 

输出：

{ 
    "address": { 
        "zipcode": 12345, 
        "street": "21 2nd St", 
        "city": "New York", 
        "state": "NY" 
       }, 
    "userIntro": { 
         "last_name": "Smith", 
         "first_name": "John", 
         "age": "28" 
        } 
}