尝试在MySQL查询中使用多个WHERE命令[Not Working]
问题描述:
如果我的查询字符串与我指定的表的列值匹配,我有一个数据库,我想要更改某个表的行值的状态..尝试在MySQL查询中使用多个WHERE命令[Not Working]
这是我迄今为止所做的...
<?php
$connection = mysql_connect("localhost", "creative_db", "samplepassword");
$db = mysql_select_db("creative_dbgogo", $connection);
$slct = mysql_query("UPDATE zombie_links SET link_status = 'discard' WHERE link_url = '%pills%' OR link_url_title = '%pills%' OR link_title = '%pills%' OR link_title_url = '%pills%' OR link_content = '%pills%' OR link_summary = '%pills%' OR link_tags= '%pills%' ") or die(mysql_error());
?>
我在做什么错?请帮忙!
答
=
不采用通配符。我想你想要like
:
UPDATE zombie_links
SET link_status = 'discard'
WHERE link_url like '%pills%' OR link_url_title like '%pills%' OR link_title like '%pills%' OR
link_title_url like '%pills%' OR link_content like '%pills%' OR
link_summary like '%pills%' OR link_tags like '%pills%';
+0
谢谢! :-) 有效!! :-) – Swayam 2014-09-29 16:08:14
答
试试这个
$slct = mysql_query("UPDATE zombie_links SET link_status = 'discard' WHERE link_url like '%pills%' OR link_url_title like '%pills%' OR link_title like '%pills%' OR link_title_url like '%pills%' OR link_content like '%pills%' OR link_summary like '%pills%' OR link_tags like '%pills%' ") or die(mysql_error());
你不说是什么问题,你遇到。 – arkyc 2014-09-29 02:52:07
@arkyc问题是,没有错误正在显示,也没有在我的数据库上工作.. – Swayam 2014-09-29 16:00:01