有趣的循环和布尔值

问题描述：

我为我的编程类编码，如果在一个2层多维数组中有4个相等的值，以对角线，垂直或水平方式连续读取，那么这个编程类应该被读取和罚款。这是我的代码。有趣的循环和布尔值

public static boolean isConseccutiveFour (int[][] matrix){ 
    //creates a boolean to give answer later on 
    boolean connection = true; 
    int[][] consecFour = matrix; 
    //incrementing for loops that move through the two arrays by going horizontally then diagonally 
    for (int Y = 0; Y < consecFour.length - 3; Y++){ 
     for(int X= 0; X < consecFour[0].length - 3; X++){ 
      //if statement used to give the proper constraints for diagonal check 
      if ((consecFour.length - Y < 3) && (consecFour[0].length - X < 3)){ 
       if (consecFour[X][Y] == consecFour[X + 1][Y + 1] && consecFour[X][Y] == consecFour[X+2][Y+2] && consecFour[X][Y] == consecFour[X+3][Y+3]) 
        connection = true; 
      } 
      //if statement used to give the proper constraints for diagonal check 
      else if ((consecFour.length - Y < 3) && (consecFour[0].length < 3)){ 
       if (consecFour[X][Y] == consecFour[X-1][Y-1] && consecFour[X][Y] == consecFour[X-2][Y-2] && consecFour[X][Y] == consecFour[X-3][Y-3]) 
        connection = true; 
      } 
      //if statement used to give the proper constraints for horizontal check 
      else if (consecFour[0].length - X < 3){ 
       if(consecFour[X][Y] == consecFour[X+1][Y] && consecFour[X][Y] == consecFour[X+2][Y] && consecFour[X][Y] == consecFour[X+3][Y]) 
        connection = true; 
      } 
      //if statement used to give the proper constraints for vertical check 
      else if (consecFour.length - Y < 3){ 
       if (consecFour[X][Y] == consecFour[X][Y + 1] && consecFour[X][Y] == consecFour[X][Y+2] && consecFour[X][Y] == consecFour[X][Y+3]) 
        connection = true; 
      } 
     } 
    } 
    //return statement of boolean value 
    return connection;

我现在的问题是，它总是返回true，无论放在什么数组，我知道这似乎是一个愚蠢的错误，但我实在找不到什么是错的。我在我的主要语句中有这个方法称为检查，以确保输入数组的长度大于4和宽度大于4.这是在Java中，因为你已经知道和答案将不胜感激。

答

错误是你从来没有连接到false，只需添加最后一个else并使连接等于false或使连接默认为false不为true。

public static boolean isConseccutiveFour (int[][] matrix){ 
     //creates a boolean to give answer later on 
     boolean connection = false; 
     int[][] consecFour = matrix; 
     //incrementing for loops that move through the two arrays by going horizontally then diagonally 
     for (int Y = 0; Y < consecFour.length - 3; Y++){ 
      for(int X= 0; X < consecFour[0].length - 3; X++){ 
       //if statement used to give the proper constraints for diagonal check 
       if ((consecFour.length - Y < 3) && (consecFour[0].length - X < 3)){ 
        if (consecFour[X][Y] == consecFour[X + 1][Y + 1] && consecFour[X][Y] == consecFour[X+2][Y+2] && consecFour[X][Y] == consecFour[X+3][Y+3]) 
         connection = true; 
       } 
       //if statement used to give the proper constraints for diagonal check 
       else if ((consecFour.length - Y < 3) && (consecFour[0].length < 3)){ 
        if (consecFour[X][Y] == consecFour[X-1][Y-1] && consecFour[X][Y] == consecFour[X-2][Y-2] && consecFour[X][Y] == consecFour[X-3][Y-3]) 
         connection = true; 
       } 
       //if statement used to give the proper constraints for horizontal check 
       else if (consecFour[0].length - X < 3){ 
        if(consecFour[X][Y] == consecFour[X+1][Y] && consecFour[X][Y] == consecFour[X+2][Y] && consecFour[X][Y] == consecFour[X+3][Y]) 
         connection = true; 
       } 
       //if statement used to give the proper constraints for vertical check 
       else if (consecFour.length - Y < 3){ 
        if (consecFour[X][Y] == consecFour[X][Y + 1] && consecFour[X][Y] == consecFour[X][Y+2] && consecFour[X][Y] == consecFour[X][Y+3]) 
         connection = true; 
       } 
      } 
     } 
     //return statement of boolean value 
     return connection;

所以我做了你所说的，并创建了一个else语句，使connection = false;并且原始方程式也是相同的，但现在所做的只是返回错误的答案。即使当我硬编码一个连接等于false。 – JamesJSchindler

我的答案是要做一个默认为false或添加一个else语句，但我认为你应该使条件（（consecFour.length - Y

答案是正确（+1）。我添加了一个可能有所帮助的解释。 – c0der

答

由于user7790438回答正确，connection永远不会设置为false，那么方法只能返回true。为了说明它，这里是你的代码的骨架：

public static boolean isConseccutiveFour (int[][] matrix){ 

     boolean connection = true; 

     for (....){ 

       if (....){ 
         .... 
         connection = true; 
       } 

       else if (....){ 
         .... 
         connection = true; 
       } 
       else if (....){ 
         .... 
         connection = true; 
       } 

       else if (....){ 
         .... 
         connection = true; 
       }  
     } 

     return connection; 
    }

你能看到connection = false1地方？

有趣的循环和布尔值

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