递归函数返回空数组
问题描述：
我已经创建了以下函数，旨在将字符串拆分为请求的点并返回发生的单词数组。递归函数返回空数组
目前，该函数的工作原理是，当参数一个接一个地传递，但不传递给一个数组时，我想覆盖这两个选项。
我试图强制函数重新运行自己，如果参数被发现是一个数组（第15行），但第二次运行后返回的数组是空的。
问：
如何解决我的代码，这样的功能的正常使用，即使参数是一个数组内传递？
代码：
function string(str) {
/* Throw error if 'string' is not a string */
if (str.constructor !== String) throw new Error("Argument is not a string.");
else return {
splitAt: function() {
var
args = arguments,
len = args.length,
arg = args[0],
index = 0,
prev = 0,
arr = [];
/* If the indices are passed in an array ([4, 5, 8, 12]) rerun the function */
if (args[0].constructor === Array) string(str).splitAt.apply(this, args[0]);
else for (; index < len; index++, arg = args[index], prev = args[index - 1]) {
/* The first time cut the string at the requested point and save both parts */
if (!index) {
arr[index] = str.substr(0, arg);
arr[index + 1] = str.substr(arg);
/* From then on overwrite the last element of the array */
} else {
arr[index + 1] = arr[index].substr(arg - prev);
arr[index] = arr[index].substr(0, arg - prev);
}
}
return arr;
}
}
}
/* Arguments passed one after another */
console.log(string("Whatadayit'sbeen!").splitAt(4, 5, 8, 12));
/* Arguments passed in an array */
console.log(string("Whatadayit'sbeen!").splitAt([4, 5, 8, 12]));
答
我想你错过了一回这里：
function string(str) {
/* Throw error if 'string' is not a string */
if (str.constructor !== String) throw new Error("Argument is not a string.");
else return {
splitAt: function() {
var
args = arguments,
len = args.length,
arg = args[0],
index = 0,
prev = 0,
arr = [];
/* If the indices are passed in an array ([4, 5, 8, 12]) rerun the function */
if (args[0].constructor === Array)
return string(str).splitAt.apply(this, args[0]);
else for (; index < len; index++, arg = args[index], prev = args[index - 1]) {
/* The first time cut the string at the requested point and save both parts */
if (!index) {
arr[index] = str.substr(0, arg);
arr[index + 1] = str.substr(arg);
/* From then on overwrite the last element of the array */
} else {
arr[index + 1] = arr[index].substr(arg - prev);
arr[index] = arr[index].substr(0, arg - prev);
}
}
return arr;
}
}
}
/* Arguments passed one after another */
console.log(string("Whatadayit'sbeen!").splitAt(4, 5, 8, 12));
debugger;
/* Arguments passed in an array */
console.log(string("Whatadayit'sbeen!").splitAt([4, 5, 8, 12]));
+0
是的，一个简单的**'返回**。谢谢@MaxLeizerovich :) –
答
我已经离开所有代码机智，但将部分接受数组参数。
function string(str) {
/* Throw error if 'string' is not a string */
if (str.constructor !== String) throw new Error("Argument is not a string.");
else return {
splitAt: function() {
var
args = arguments,
len = args.length,
arg = args[0],
index = 0,
prev = 0,
arr = [];
/* If the indices are passed in an array ([4, 5, 8, 12]) rerun the function */
if (args[0].constructor === Array) {
return string(str).splitAt.apply(this, args[0]);
} else for (; index < len; index++, arg = args[index], prev = args[index - 1]) {
/* The first time cut the string at the requested point and save both parts */
if (!index) {
arr[index] = str.substr(0, arg);
arr[index + 1] = str.substr(arg);
/* From then on overwrite the last element of the array */
} else {
arr[index + 1] = arr[index].substr(arg - prev);
arr[index] = arr[index].substr(0, arg - prev);
}
}
return arr;
}
}
}
/* Arguments passed one after another */
console.log(string("Whatadayit'sbeen!").splitAt(4, 5, 8, 12));
/* Arguments passed in an array */
console.log(string("Whatadayit'sbeen!").splitAt([4, 5, 8, 12]));
那么，你为什么要删除其他问题吗？ – zerkms
我很快就会取消删除。我只是等到我可以接受。 –