将元素推送到队列时出现分段错误
我在很长一段时间内在Cpp中编程,而我被困在一个地方。下面的代码中给出(其长所以患者):将元素推送到队列时出现分段错误
bool mazerouter(int xs, int ys, int ps, int xt, int yt, int pt)
{
int n = gn; int w = gw;
// The expansion list as maintained by the maze router. Could be declared as a class variable
// but then, we need to find a way to empty the queue every time mazerouter is exited.
queue <Wire_seg> explist;
// Step 1: mark all the track segments that are available and adjacent to target as "t".
// this depends on pin number.
vector < vector<int> > target = getWireSegments(xt, yt, pt);
//int skip = 1/fc_in;
int i,j;
std::vector < std::vector <Wire_seg> > HorzWire = fpga.getHorzWire();
std::vector < std::vector <Wire_seg> > VertWire = fpga.getVertWire();
for (i = 0; i < target.size(); i = i+2)
{
if (pt == 1 || pt == 3)
{
if (VertWire[ target[i][0]][ target[i][1] ].getTag() == "a")
VertWire[ target[i][0] ][ target[i][1] ].setTag("t");
}
else if (pt == 2)
{
if (HorzWire[ target[i][0]][ target[i][1] ].getTag() == "a")
HorzWire[ target[i][0] ][ target[i][1] ].setTag("t");
}
} cout<<"Completed routing step 1\n";
// Step 2: mark all the track segments that are available and adjacent to source as "o".
// Push all the wire_segs in expansion list.
vector < vector<int> > source = getWireSegments(xs, ys, ps);
//skip = 1/fc_out;
len = 0; // for initialization of the source wire segments
for (i = 0; i < source.size(); i = i+1)
{
if (HorzWire[ source[i][0] ][ source[i][1] ].getTag() == "a")
{
HorzWire[ source[i][0] ][ source[i][1] ].setNtag(0);
HorzWire[ source[i][0] ][ source[i][1] ].setTag("u");
explist.push(HorzWire[ source[i][0] ][ source[i][1] ]);
}
} cout<<"Completed routing step 2 and expansion list size: "<<explist.size()<<"\n";
// The while loop
bool pathfound = false;
vector < vector <int> > h;
vector < vector <int> > v;
while (!explist.empty())
{
Wire_seg ws = explist.front();
cout<<"Completed routing step 3 substep 1 with front's tag:"<<explist.front().getTag()<<"\n";
explist.pop();
h = ws.getHorzCon();
v = ws.getVertCon();
len = ws.getNtag() + 1;
int a;
for (a = 0; a < h.size(); a++)
{
if (HorzWire[ h[a][0] ][ h[a][1] ].getTag() == "t")
{
cout<<"target hit in horzwire\n";
pathfound = true;
//path.push_back( vector <string>()); pl++;
//path.at(pl).push_back(fpga.getHorzWire(h[a][0], h[a][1]).getUid());
break;
}
else if (HorzWire[ h[a][0] ][ h[a][1] ].getTag() == "a")
{
HorzWire[ h[a][0] ][ h[a][1] ].setTag("u");HorzWire[ h[a][0] ][ h[a][1] ].setNtag(len);
cout<<"target not found, pushing horzwire("<<h[a][0]<<","<<h[a][1]<<") in explist with new tag:"<<HorzWire[ h[a][0] ][ h[a][1] ].getTag()<<"\n";
explist.push(HorzWire[ h[a][0] ][ h[a][1] ]);
}
}
cout<<"Completed routing step 3 substep 2\n";
for (a = 0; a < v.size(); a++)
{
if (VertWire[ v[a][0] ][ v[a][1] ].getTag() == "t")
{
pathfound = true;
//path.push_back( vector <string>()); pl++;
//path.at(pl).push_back(fpga.getVertWire(v[a][0], v[a][1]).getUid());
break;
}
else if (VertWire[ v[a][0] ][ v[a][1] ].getTag() == "a")
{
VertWire[ v[a][0] ][ v[a][1] ].setTag("u"); VertWire[ v[a][0] ][ v[a][1] ].setNtag(len);
// the following is the line causing trouble
explist.push(VertWire[ v[a][0] ][ v[a][1] ]); <=================================================================
cout<<"target not found, pushing vertwire("<<v[a][0]<<","<<v[a][1]<<") in explist with new tag:"<<VertWire[ v[a][0] ][ v[a][1] ].getTag()<<"\n";
}
}
h.clear();
v.clear();
cout<<"Completed routing step 3 substep 3 and expansion list size: "<<explist.size()<<"\n";
}// end while
cout<<"Completed routing step 3\n";
return pathfound;
}// end mazerouter
我正在为线分段故障“explist.push(VertWire [V [A] [0]] [V [A] [ 1]]);“已在代码中标记为”< ==“。一旦我评论该行并运行代码,我没有任何错误,但是当然,我找不到解决我的问题的方法。我在做什么错误?任何事情都会有很大的帮助。提前致谢
这个函数做了什么:给定源块(xs,ys)和传入方向(ps,有四个值分别对应东,西,北,南)和目标块(xs,ys)和输出方向(pt,与ps相同),我需要找到连接它们的路线,实际上,我正在FPGA中实现路由,其中Wire_seg是逻辑块之间的导线段的类(它是作为Logic_Block类实现的),我需要在逻辑块之间进行路由。就VertWire [v [a] [0]] [v [a] [1]]'的打印值而言,它是一个类,因此我正在访问它的成员变量标签以确保它存在。
@daniel:我已经在使用g ++编译器。
为 “Wire_seg.h” 的代码是:
class Wire_seg
{
// the track number for each wire segment, varies from 0 to w-1.
int tno;
// the orientation of the wire segment.
char ornt;
// vector to store the indices of all possible connections that can be made from
// this wire segment.
std::vector < std::vector<int> > horz_con;
std::vector < std::vector<int> > vert_con;
//an unique id given to each wire of the following format "ornt:row:col"
std::string uid;
// The tag that helps determine whether this wire is availabel for a path or not.
// initially all wires are available.
std::string tag;
int ntag;
public:
Wire_seg()
{
tag = "a";
}
void setHorzCon(std::vector < std::vector<int> > h)
{
horz_con = h;
}
void setVertCon(std::vector < std::vector<int> > v)
{
vert_con = v;
}
void setTno(int t)
{
tno = t;
}
void setOrnt(char orientation)
{
ornt = orientation;
}
void setUid(std::string id)
{
uid = id;
}
void setTag(std::string t)
{
tag.assign(t);
}
void setNtag(int t)
{
ntag = t;
}
int getTno()
{
return tno;
}
char getOrnt()
{
return ornt;
}
std::vector < std::vector<int> > getHorzCon()
{
return horz_con;
}
std::vector < std::vector<int> > getVertCon()
{
return vert_con;
}
std::string getUid()
{
return uid;
}
std::string getTag()
{
return tag;
}
int getNtag()
{
return ntag;
}
};
我希望这使得问题更加清晰。
您对std::deque
的使用看起来很安全,所以如果您遇到分段错误,您可能正在编译一个不执行边界检查的std::vector
实现。如果可以的话,打开它。
如果您的环境不提供边界检查,请尝试使用g ++(它会)。或者在std::vector
附近写一个简单的包装类,给你所需的接口:size()
和operator[]
似乎是你所需要的。你自己的边界检查也是如此。然后,您将能够看到您在过去的矢量末尾访问的位置。
你如何做你刚刚说的? –
你能解释一下这个函数的作用吗?它看起来像你试图用广度优先搜索来解决迷宫,这是正确的吗?什么是电线变量? – Pubby
你试过打印出VertWire [v [a] [0]] [v [a] [1]]的值吗?如果它崩溃,你知道你正在访问超出界限的数组而导致UB。 –
请发布'Wire_seg'的代码,尤其是构造函数/析构函数。 – NPE