简单的PHP上传表单不起作用

问题描述：

在处理写入目录时，我似乎遇到了很多问题。如果有人可以请看这个脚本，并告诉我为什么它不起作用，我会很感激。简单的PHP上传表单不起作用

从窗体上传文件后，我什么也没有得到。它没有输出任何错误，只是刷新了。

感谢，LEA

<?php include ('config.php'); 
if(isset($_POST['submit'])) { 

$target = ''.$_SERVER['DOCUMENT_ROOT'].'/images/'; 
$target = $target . basename($_FILES['photo']['name']) ; 
$url = basename($_FILES['photo']['name']) ; 

if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { 
$moved = "File has been moved to location $target"; 

$name = mysql_real_escape_string($_POST['photoname']); 
mysql_query("INSERT INTO photos (photo_name, photo_image) VALUES ('$name', '$url')") or die(mysql_error()); 
$success = "Photo has been added!"; 

    } else { 

$moved = "File has not been moved to $target"; 
$success = "Failed to upload:("; 

    } 

} ?> 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Photo Upload</title> 
<meta name="robots" content="index, follow" /> 
<meta name="keywords" content="" /> 
<meta name="description" content="" /> 
<link href="<?php echo $globalurl; ?>styles.css" rel="stylesheet" type="text/css" /> 
</head> 
<body> 
<div class="holder"> 
<br /><br /> 
<b>Add a new photo</b> 
<hr /> 
<br /> 
<b><?php echo "$success<br />"; ?> 
<?php echo "$moved<br />"; ?></b> 
    <form enctype="multipart/form-data" method="post" action="<?php echo $PHP_SELF; ?>"> 
    <table cellspacing="0" cellpadding="0" width="500px"> 
     <tbody> 
     <tr> 
      <td valign="top">Photo Name:</td> 
      <td valign="top"> 
      <input type="text" name="photoname" /><br /> 
      <br /> 
      </td> 
     </tr> 
     <tr> 
      <td valign="top">Photo:</td> 
      <td valign="top"> 
    <input type="file" name="photo"><br /> 
      <br /> 
      </td> 
     </tr> 
     </tbody> 
    </table> 
    <input type="submit" value="submit" /> 
    </form> 
</div> 
</body> 
</html>

答

没有检查错误PHP代码，脱颖而出的第一件事情是这样的：

isset($_POST['submit'])

始终返回false。输入类型=“提交”必须拥有的name属性“提交”发送：

<input type="submit" value="submit" name="submit" />

好的，谢谢。现在我感到愚蠢..大声笑。干杯队友，利亚 – Lea 2010-05-26 07:15:49

答

这是错误的，在提交按钮使用这样的：

<input type="submit" value="submit" name="submit" />

答

好做

<?php 
if(isset($_POST['submit'])) { 
$target = 'images/'; 
echo $target = $target . basename($_FILES['photo']['name']) ; 

if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { 
    $moved = "File has been moved to location $target"; 
    $success = "Photo has been added!"; 
} 
else { 
$moved = "File has not been moved to $target"; 
$success = "Failed to upload:("; 
    } 
} 
?> 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Photo Upload</title> 
<meta name="robots" content="index, follow" /> 
<meta name="keywords" content="" /> 
<meta name="description" content="" /> 
<link href="<?php echo $globalurl; ?>styles.css" rel="stylesheet" type="text/css" /> 
</head> 
<body> 
<div class="holder"> 
<b>Add a new photo</b> 
<?php echo "$success<br />"; ?> 
<?php echo "$moved<br />"; ?> 
    <form enctype="multipart/form-data" method="post" action="<? echo $_SERVER['PHP_SELF']; ?>"> 
    <table cellspacing="0" cellpadding="0" width="500px"> 
     <tbody> 
     <tr> 
      <td valign="top">Photo Name:</td> 
      <td valign="top"> 
      <input type="text" name="photoname" /><br /> 
      <br /> 
      </td> 
     </tr> 
     <tr> 
      <td valign="top">Photo:</td> 
      <td valign="top"> 
    <input type="file" name="photo"> 
      </td> 
     </tr> 
     </tbody> 
    </table> 
    <input type="submit" value="submit" id="submit" name="submit" /> 
    </form> 
</div> 
</body> 
</html>

简单的PHP上传表单不起作用

相关推荐