在php
问题描述:
中将HTTP内容类型响应设置为“application/json”我有问题。我有如下因素条件:在php
You should return an HTTP 500 status code and more details about the error in the message body. Set the HTTP content type response to “application/json”.The error detail must be in JSON format as described below:
{
"ErrorCode" : 402,
"ErrorMessage" : "Item"
}
我想是这样的:
if(!Gain::verifyIfUserExistByIdm($aOutput['UserId'])){
header("HTTP/1.0 500 Internal Server Error");
return json_encode(array('ErrorCode'=>407,'ErrorMessage'=>'Error'));
die();
}
但是不行,你能帮帮我吗? THX提前
答
你需要输出的JSON(不仅仅是归还),并让客户知道内容是JSON通过设置Content-Type
:
// The user does not exist
if (! Gain::verifyIfUserExistByIdm($aOutput['UserId'])) {
// If the user does not exist then "Forbidden" would make sense
header("HTTP/1.0 403 Forbidden");
// Let the client know that the output is JSON
header('Content-Type: application/json');
// Output the JSON
echo json_encode(array(
'ErrorCode' => 407,
'ErrorMessage' => 'Error',
));
// Always terminate the script as soon as possible
// when setting error headers
die;
}
'标题(“内容类型:应用程序/ json');' –
我需要添加这个'header' – TanGio
我想你想要这个 - http://stackoverflow.com/questions/4162223/how-to-send-500-internal-server-error-error -from-a-php-script,并且不需要返回。简单地退出;标题足够后。 – ArtisticPhoenix