XCode：苹果Mach-O链接器错误与新的iOS 6 ABAddressBook函数

Question

我正在运行Xcode 4.2与导入IOS 6 SDK（旧的Mac无法运行XCode 4.5）。我的应用程序配置了4.3的iOS部署目标，6.0的基本SDK以及仅ARMv7的体系结构。

我试图更新我以前的工作应用程序以请求访问用户的地址簿（现在是iOS 6的要求（使用新的iOS 6功能））的权限。不幸的是，我收到以下Apple的Mach-O链接错误：

Ld /Users/Blake/Library/Developer/Xcode/DerivedData/MyApp-ercibgqhpidlmwflixmwbvruyctz/Build/Products/Debug-iphoneos/MyApp.app/MyApp normal armv7 cd /Users/Blake/Desktop/MyApp/MyApp setenv IPHONEOS_DEPLOYMENT_TARGET 4.3 setenv PATH "/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin:/Developer/usr/bin:/usr/bin:/bin:/usr/sbin:/sbin" /Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/clang -arch armv7 -isysroot /Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS5.0.sdk -L/Users/Blake/Library/Developer/Xcode/DerivedData/MyApp-ercibgqhpidlmwflixmwbvruyctz/Build/Products/Debug-iphoneos -L/Users/Blake/Desktop/MyApp/MyApp/../../../Downloads/ScannerKit-Latest/Demo/Libraries/ScannerKit -F/Users/Blake/Library/Developer/Xcode/DerivedData/MyApp-ercibgqhpidlmwflixmwbvruyctz/Build/Products/Debug-iphoneos -filelist /Users/Blake/Library/Developer/Xcode/DerivedData/MyApp-ercibgqhpidlmwflixmwbvruyctz/Build/Intermediates/MyApp.build/Debug-iphoneos/MyApp.build/Objects-normal/armv7/MyApp.LinkFileList -dead_strip -all_load -lstdc++ -fobjc-arc -miphoneos-version-min=4.3 -framework AddressBook -framework AddressBookUI -framework UIKit -framework Foundation -framework CoreGraphics -lScannerKit -framework AVFoundation -framework CoreMedia -framework SystemConfiguration -framework CoreVideo -liconv -framework AudioToolbox -framework QuartzCore -o /Users/Blake/Library/Developer/Xcode/DerivedData/MyApp-ercibgqhpidlmwflixmwbvruyctz/Build/Products/Debug-iphoneos/MyApp.app/MyApp

Undefined symbols for architecture armv7:
"_ABAddressBookRequestAccessWithCompletion", referenced from: -[ServerConnect parserDidEndDocument:] in ServerConnect.o "_ABAddressBookGetAuthorizationStatus", referenced from: -[ServerConnect parserDidEndDocument:] in ServerConnect.o "_ABAddressBookCreateWithOptions", referenced from: -[ServerConnect parserDidEndDocument:] in ServerConnect.o ld: symbol(s) not found for architecture armv7 clang: error: linker command failed with exit code 1 (use -v to see invocation)

我最好的猜测是的XCode 4.2正在寻找在iPhoneOS5.0.sdk而不是我iPhoneOS6.0.sdk对建筑的ARMv7。但是，我无法看到我可以在哪里解决这个问题。有没有其他人遇到过这个问题？感谢您提前提供任何帮助！

我的代码（供参考）：

// Fetch the address book 
//Check if we are using iOS6 
if ([self isABAddressBookCreateWithOptionsAvailable]) { 
     ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, NULL); 

     if (ABAddressBookGetAuthorizationStatus() == 0) { 
      ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) { 
       // First time access has been granted 
       [self searchForPersonInAddressBook:addressBook withName:fullName]; 
      }); 
     } 
     else if (ABAddressBookGetAuthorizationStatus() == 3) { 
      // The user has previously given access 
      [self searchForPersonInAddressBook:addressBook withName:fullName]; 
     } 
     else { 
      // The user has previously denied access 
      UIAlertView *deniedAccess=[[UIAlertView alloc] initWithTitle:@"Unable to Access Address Book" message:@"Change App Privacy Settings" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil]; 
      [deniedAccess show]; 
     } 
    } 
    //If using iOS 4/5 
    else { 
     ABAddressBookRef addressBook = ABAddressBookCreate(); 
     [self searchForPersonInAddressBook:addressBook withName:fullName]; 
    } 
} 

- (void)searchForPersonInAddressBook:(ABAddressBookRef)ab 
       withName:(NSString *)fn 
{ 
// Search for the person in the address book 
CFArrayRef person = ABAddressBookCopyPeopleWithName(ab, (__bridge CFStringRef)fn); 
// Display message if person not found in the address book 
if ((person != nil) && (CFArrayGetCount(person) == 0)) { 
    // Show an alert if name is not in Contacts 
    UIAlertView *saveContact=[[UIAlertView alloc] initWithTitle:@"Save New Contact to iPhone?" message:fn delegate:self cancelButtonTitle:@"No" otherButtonTitles:@"Save!", nil]; 
    saveContact.tag = 2; 
    [saveContact show]; 
} 
} 

- (BOOL)isABAddressBookCreateWithOptionsAvailable 
{ 
    return &ABAddressBookCreateWithOptions != NULL; 
} 

Answer 1

我通过弱解决我的问题“与库链接二进制”我的目标构建的部分链接地址簿框架中添加AddressBook.framework阶段设置（“可选”而不是“必需”）。

此外，我相信有一个XCode4.2错误，它复制设备目标。出于某种原因，选择重复后，我的应用程序能够编译（请参阅以下链接：How to access weak linked framework in iOS?）。

Answer 2

那是，如果你不框架链接到你的项目，你通常会得到错误的类型。所以，你可能导入了头文件（因此没有编译时错误），但是，你没有从TargetName->Build Phases->Link Binary With Libraries