if命令是否继续此代码的正确方法？

问题描述：

我不知道如何向我的脚本添加yes或no部分。我想我应该使用if命令，但我不确定我会怎么写，因为我看到的所有示例都使用数字。这是我目前有，if命令是否继续此代码的正确方法？

print("Hi there! I would like to welcome you to this program! Please, tell me your name.: ") 
name = gets 
puts("Hello there, " + name) 
print("I'm still testing everything out so please, bear with me. Now, how old are you?: ") 
age = gets 
puts("So you're " + age.chomp + " years old. ") 
print("I am now going to ask you a few questions. I'd like you to answer as best you can. ") 
print("Are you in school? Please answer, yes or no.: ")

感谢您的所有信息。我将尝试所有这些以了解每个人是如何工作的。 – Cristhian 2014-09-05 01:57:28

我无法弄清楚如何获得返回命令的工作，但它确实给了我一个工作的轻微解决方法的想法。通过这里的答案，我能够使我的脚本更加复杂一点，我对它的结果感到满意。再次感谢！ – Cristhian 2014-09-05 02:54:04

答

除了其他答案，您还可以使用case语句来检查您的字符串，然后提供正确的答案。

例如，

print "Enter your grade: " 
grade = gets.chomp 
case grade 
when "A" 
    puts 'Well done!' 
when "B" 
    puts 'Try harder!' 
when "C" 
    puts 'You need help!!!' 
else 
    puts "You just making it up!" 
end

答

对于初学者，你的代码是伟大的，而现在你并不真正需要考虑重构你的代码。你可以添加这个。

print("Are you in school? Please answer, yes or no.: ") 
answer_1 = gets.chomp 
puts "your question #{answer_1}" if answer_1.eql?("yes")

这是单行控制语句。但是你也可以使用多行如果：elsif ... – 2014-09-05 01:38:00

答

添加一些检查您输入，继承人应该是一个小递归函数，记住，它的无限直到用户输入的东西是正确的。

def get_name 
    name = gets 
    if name 
    puts "Hello there, " + name 
    else 
    puts 'Please put a correct name' 
    return get_name 
    end 
end 

def get_age 
    age = gets 
    if not age =~ /\A\d+\z/ 
    puts("So you're " + age.chomp + " years old. ") 
    else 
    puts 'input is not a number' 
    return get_age 
    end 
end 

print("Hi there! I would like to welcome you to this program! Please, tell me your name.: ") 
get_name 

print("I'm still testing everything out so please, bear with me. Now, how old are you?: ") 

get_age 
print("I am now going to ask you a few questions. I'd like you to answer as best you can. ") 
print("Are you in school? Please answer, yes or no.: ")

if命令是否继续此代码的正确方法？

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