Swift:如何将JSON字符串与Alamofilre或SwiftyJSON转换为ObjectMapper?
问题描述:
我目前使用
ObjectMapper斯威夫特用于映射JSON对象从API到模型对象
Swift:如何将JSON字符串与Alamofilre或SwiftyJSON转换为ObjectMapper?
但我的RESTful API返回的API看起来像这样
:
{
success: true,
data:
[{
"stats":{
"numberOfYes":0,
"numberOfNo":2,
"progress":{
"done":false,
"absolute":"2/100",
"percent":2
}
},
"quickStats":null,
"uid":5,
"name":"Flora",
"imageArray":[
"http://s3.com/impr_5329beac79400000",
"http://s3.com/impr_5329beac79400001"
],
"metaData":{
"description":"Floral Midi Dress",
"price":"40$"
}
}]
}
在数据节点阵列我不能看直到使用此代码映射
let json = JSON(responseObject!)
for tests in json["impressions"][0] {
let test = Mapper<myTests>().map(tests)
println(test?.impressionID)
}
我该如何解决? 由于
** 编辑 ** 我发现溶液类似@tristan_him
ObjectModel映射结构
class Response: Mappable {
var success: Bool?
var data: [Data]?
required init?(_ map: Map) {
mapping(map)
}
func mapping(map: Map) {
success <- map["success"]
data <- map["data"]
}
}
class Data: Mappable {
var uid: Int?
var name: String?
// add other field which you want to map
required init?(_ map: Map) {
mapping(map)
}
func mapping(map: Map) {
uid <- map["uid"]
name <- map["name"]
}
}
映射与Alamofire响应
let response: Response = Mapper<Response>().map(responseObject)!
for item in response.data! {
let dataModel: Data = item
println(dataModel.name)
}
答
您可以使用下面的类结构映射的JSON以上:
class Response: Mappable {
var success: Bool?
var data: [Data]?
required init?(_ map: Map) {
mapping(map)
}
func mapping(map: Map) {
success <- map["success"]
data <- map["data"]
}
}
class Data: Mappable {
var uid: Int?
var name: String?
// add other field which you want to map
required init?(_ map: Map) {
mapping(map)
}
func mapping(map: Map) {
uid <- map["uid"]
name <- map["name"]
}
}
然后你可以如下图吧:
let response = Mapper<Response>().map(responseObject)
if let id = response?.data?[0].uid {
println(id)
}
谢谢@triton_him – Thunderbird
@tristan_him,我们可以把“回应'和'Data'类在两个不同的Response.swift和Data.Swift文件中,或者我们需要将它们保存在单个.swift文件中? –
@AshishPisey,它应该以任何方式工作。这取决于你以及你想如何构建你的项目。 –