如何实现使用一个序多个节奏在java中
问题描述:
我一直对音乐节拍器应用在Java和我无意中发现的并发症。考虑下面这是取自代码:https://community.oracle.com/thread/2135272。这里的实现与我为获得多个节奏所做的相似。我有这个唯一的问题是,它使事情有点乱,我希望也许有人可以优选通过使用一个序提供另一种方式,以具有多节奏。如何实现使用一个序多个节奏在java中
import java.util.*;
import javax.swing.*;
import javax.sound.midi.*;
public class MetronomeTestApplet extends JApplet
{
public void init()
{
MetronomeTest metTest = new MetronomeTest();
metTest.play();
}
}
class MetronomeTest
{
Sequencer sequencer1=null;
Sequencer sequencer2=null;
Sequence sequence1=null;
Sequence sequence2=null;
Track track1=null;
Track track2=null;
MidiEvent newEvent=null;
int volume = 90;
int tempo = 100;
public MetronomeTest()
{
try
{ // SEQUENCER 1
sequencer1 = MidiSystem.getSequencer();
sequencer1.open();
sequence1 = new Sequence(Sequence.PPQ, 16);
track1 = sequence1.createTrack();
ShortMessage instrumentMsg = new ShortMessage();
instrumentMsg.setMessage(ShortMessage.PROGRAM_CHANGE, 0, 115, 0); // 115 == woodblock
track1.add(new MidiEvent(instrumentMsg, 0));
// SEQUENCER 2
sequencer2 = MidiSystem.getSequencer();
sequencer2.open();
sequence2 = new Sequence(Sequence.PPQ, 16);
track2 = sequence2.createTrack();
instrumentMsg = new ShortMessage();
instrumentMsg.setMessage(ShortMessage.PROGRAM_CHANGE, 0, 117, 0); // 117 == melodic tom
track2.add(new MidiEvent(instrumentMsg, 0));
}
catch (Exception e) { e.printStackTrace(); }
}
public void destroy()
{
sequencer1.stop();
sequencer1.close();
sequencer2.stop();
sequencer2.close();
}
public void play()
{
try
{
// LOAD SEQUENCE 1
for (int i=0; i<4; i++)
{
ShortMessage noteOnMsg = new ShortMessage();
noteOnMsg.setMessage(ShortMessage.NOTE_ON, 0, 60, volume);
track1.add(new MidiEvent(noteOnMsg, 0 + 16*i));
ShortMessage noteOffMsg = new ShortMessage();
noteOffMsg.setMessage(ShortMessage.NOTE_OFF, 0, 60, volume);
track1.add(new MidiEvent(noteOffMsg, 16 + 16*i));
}
// LOAD SEQUENCE 2
for (int i=0; i<8; i++)
{
ShortMessage noteOnMsg = new ShortMessage();
noteOnMsg.setMessage(ShortMessage.NOTE_ON, 0, 60, volume);
track2.add(new MidiEvent(noteOnMsg, 0 + 8*i));
ShortMessage noteOffMsg = new ShortMessage();
noteOffMsg.setMessage(ShortMessage.NOTE_OFF, 0, 60, volume);
track2.add(new MidiEvent(noteOffMsg, 8 + 8*i));
}
// LOAD AND START SEQUENCERS
sequencer1.setSequence(sequence1);
sequencer1.setTempoInBPM(tempo);
sequencer1.setLoopCount(Sequencer.LOOP_CONTINUOUSLY);
sequencer2.setSequence(sequence2);
sequencer2.setTempoInBPM(tempo);
sequencer2.setLoopCount(Sequencer.LOOP_CONTINUOUSLY);
sequencer1.start();
sequencer2.start();
}
catch (Exception e) { e.printStackTrace(); }
}
}
为什么你还要说你需要多个节奏当两个您的序列是一样的速度运行? – jaket 2015-02-11 17:27:54
感谢您的注意。我试图运行不同的分辨率和不同的速度 – 2015-02-11 18:11:18