泛型类型的初始化器不会被快速继承吗？
这里是我的代码：泛型类型的初始化器不会被快速继承吗？
public class A<T : Any> {
public init(n : Int) {
print("A")
}
}
public class B : A<Int> {
}
public class C : B {
}
let x = C(n: 123)
这种失败的编译和破口大骂这样的错误：
repl.swift:9:9: error: 'C' cannot be constructed because it has no accessible initializers
下面的代码可以编译。
public class A {
public init(n : Int) {
print("A")
}
}
public class B : A {
}
public class C : B {
}
let x = C(n: 123)
如果没有指定泛型类型初始化需求类型继承？
========以下其他=======
“Superclass initializers are inherited in certain circumstances, but only when it is safe and appropriate to do so. For more information, see Automatic Initializer Inheritance below.”
---Apple Inc. “The Swift Programming Language (Swift 2)” iBooks.
这
“However, superclass initializers are automatically inherited if certain conditions are met.”
“Assuming that you provide default values for any new properties you introduce in a subclass, the following two rules apply:” Rule 1 “If your subclass doesn’t define any designated initializers, it automatically inherits all of its superclass designated initializers.” Rule 2 “If your subclass provides an implementation of all of its superclass designated initializers—either by inheriting them as per rule 1, or by providing a custom implementation as part of its definition—then it automatically inherits all of the superclass convenience initializers.”
当寻找到的第一个代码，子类B没有按没有定义任何指定的初始化器，它应该自动继承它的所有超类指定的初始化器，那些来自A<Int>的初始化器。但实际上它并没有与我连接。
那怎么样？我尝试使用override代码和super.init，这不是错误。我认为你不必使用泛型类型来初始化函数。
试图把控初始化函数在B类和C类 这个样子，
public override init(n:Int) { super.init(n: n) }
此处还观察到：http://stackoverflow.com/questions/31040044/swift-generic-superclass-init-not-accesible-when-constructing-its-subclass。 –
某人已经在swift jira上提交了一张票https://bugs.swift.org/projects/SR/issues/SR-416 –
@AnthonyKong是的，那就是我。 – AntiMoron