当通过一个数组检查python中的重复项时列表超出范围2.7
问题描述:
目标很简单:有一个文件的x个数字用`分隔。如果文件中有数字的共享者,则应删除它们。我决定通过比较n成员与从n到len(数组)的所有其他成员来解决这个问题。代码:当通过一个数组检查python中的重复项时列表超出范围2.7
#deletes repeated numbers separated by `
questioned=open("key_file.txt",'r+')
numbers=questioned.read()
#print(numbers)
numb=[]
number=[]
for each in numbers:
if each=='`':
number.append(''.join(numb))
numb=[]
else:
numb.append(each)
i,j=0,0
for i in xrange(len(number)): #we don't need to compare last number
for j in xrange(i+1,len(number)-1):#don't need to compare to itself
#print(len(number)," ",i," ",j)
if number[i]==number[j]:
number.pop(j) #tried del number[j]
questioned.close()
但是,似乎我设法超出范围,即使我指定xrange应该转到len(array)。我的猜测是len(数字)没有被持续重新评估,导致数字超出范围,因为一堆数字被删除了? 任何指针/提示将是伟大的。非常感谢您的时间!
答
好吧,好像我的恐惧是正确的。在第二个循环中,j设法通过导致错误的len(number)...
#deletes repeated numbers separated by `
questioned=open("key_file.txt",'r+')
numbers=questioned.read()
#print(numbers)
numb=[]
number=[]
for each in numbers:
if each=='`':
number.append(''.join(numb))
numb=[]
else:
numb.append(each)
i,j=0,0
def compare(number,i,j):
if number[i]==number[j]:
number.pop(j)
compare(number,i,j)
return number
for i in xrange(len(number)):
for j in xrange(i+1,len(number)-1):
if j>len(number)-1:
break
#print(len(number)," ",i," ",j)
#try:
compare(number,i,j)
#except: print('i,j',i,' ',j,'len ',len(number))
questioned.close()
工作正常,没有try语句。我不知道为什么会发生这种情况,但似乎确实如此。如果你们有一个很好的解释:/