路径/节点顺序

问题描述:

有没有人有关于如何在XSD深一横 跟踪的路径,例如一个想法:如果我有这个模式,路径/节点顺序

<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"   targetNamespace="urn:books"   xmlns:bks="urn:books"> 
    <xsd:element name="books" type="bks:BooksForm"/> 
    <xsd:complexType name="BooksForm"> 
    <xsd:sequence> 
     <xsd:element name="book"     type="bks:BookForm"     minOccurs="0"     maxOccurs="unbounded"/> 
    </xsd:sequence> 
    </xsd:complexType> 
    <xsd:complexType name="BookForm"> 
    <xsd:sequence> 
     <xsd:element name="author" type="xsd:string"/> 
     <xsd:element name="title" type="xsd:string"/> 
     <xsd:element name="genre" type="xsd:string"/> 
     <xsd:element name="price" type="xsd:float" /> 
     <xsd:element name="pub_date" type="xsd:date" /> 
     <xsd:element name="review" type="xsd:string"/> 
    </xsd:sequence> 
    <xsd:attribute name="id" type="xsd:string"/> 
    </xsd:complexType> 
</xsd:schema> 

我怎么能得到像在C#中

path1 : books.book.author 
path2 : books.book.title 

此输出..等等

任何模式结构

没有任何人有一个想法,这个或任何良好的出发点 由于事先


感谢答复 我试图编写你的意见,但我仍然陷入

while (r.Read()) 
    {    
      switch (r.Name) 
      { 
       case "xsd:element": 
        myStringBuilder.Append(r.GetAttribute("name")); 
        break; 
       case "xsd:complexType": 
        checkComplex(r); 
        wholepath += r.GetAttribute("name"); 

        //this will only concatenate complex elements only 
        Console.WriteLine("checkComplexcaller{1}", wholepath); 
        break; 
      } 

     } 

递归部分..我没有

public static void checkComplex(/*what I should send here*/) 
    { 

     if (r.GetAttribute("name") == "xsd:complexType") 
     { 
      //What I sould to do for this recursive      

     } 
     else if (r.GetAttribute("name") == "xsd:element") 
     { 
      myStringBuilder.Append(r.GetAttribute("name")); 
     } 
    } 

怎么可能设置的路径正确

如果我得到这个权利:(伪)

(make a xml document of the xsd) 
foreach node of type xsd:element: 
    track path to the node as input 
    apend it with values of 'name' and 'type' attributes 
    if its a complex type: apply this recursively on all elements 
+0

我试图代码什么也建议我,但我被陷在某些方面 – Dena 2011-01-14 10:06:59