python minidom xml解析以获得第一个子节点的值

Question

我正在使用python minidom解析xml，但无法使其在xml下工作。我要选择的第一个服务器代码，并要名标签的值，在这种情况下，“服务器1”

<class> 
<name>MyClass</name> 
<security> 
<name>MyClass</name> 
</security> 
<server> 
<name>Server1</name> 
<ssl> 
<name>Server1</name> 
</ssl> 
<server-info> 
<name>Server1</name> 
</server-info> 
</server> 
<server> 
<name>Server2</name> 
<ssl> 
<name>Server2</name> 
</ssl> 
<server-info> 
<name>Server2</name> 
</server-info> 
</server> 
<server> 
<name>Server3</name> 
<ssl> 
<name>Server3</name> 
</ssl> 
<server-info> 
<name>Server3</name> 
</server-info> 
</server> 
</class> 

Answer 1

你必须引用XML DOM documentation和咬紧牙关。

为了得到第<server>元素，那么它的<name>：

from xml.dom import minidom 

document = minidom.parse(inputfilename) 

def findChildNodeByName(parent, name): 
    for node in parent.childNodes: 
        if node.nodeType == node.ELEMENT_NODE and node.localName == name: 
      return node 
    return None 

def getText(nodelist): 
    rc = [] 
    for node in nodelist: 
     if node.nodeType == node.TEXT_NODE: 
      rc.append(node.data) 
    return ''.join(rc) 

# Get the first of all `<server>` nodes 
server = document.getElementsByTagName('server')[0] 

# Get the first child node that is a `<name>` element 
name = findChildNodeByName(server, 'name') 
if name is not None: 
    print getText(name.childNodes)