解析XML使用XPath的
问题描述:
我试图解析Java编写,但代码SOAP请求的Java命名空间没有返回任何节点 这里是代码有谁能够找到错误解析XML使用XPath的
String xml="<soapenv:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ser=\"http://services.web.post.list.com\"><soapenv:Header><authInfo xsi:type=\"soap:authentication\" xmlns:soap=\"http://list.com/services/SoapRequestProcessor\"><!--You may enter the following 2 items in any order--><username xsi:type=\"xsd:string\">[email protected]</username><password xsi:type=\"xsd:string\">PfasdfRem91</password></authInfo></soapenv:Header></soapenv:Envelope>";
System.out.println(xml);
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document doc = builder.parse(new InputSource(new StringReader(xml)));
XPath xpath = XPathFactory.newInstance().newXPath();
// XPath Query for showing all nodes value
try
{
XPathExpression expr = xpath.compile("/soapenv:Envelope/soapenv:Header/authInfo/password");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
System.out.println("Got " + nodes.getLength() + " nodes");
// System.out.println(nodes.item(0).getNodeValue());
}
catch(Exception E)
{
System.out.println(E);
}
答
您需要设置一个NamespaceContext
上XPath
:
演示
package forum11644994;
import java.io.StringReader;
import java.util.Iterator;
import javax.xml.namespace.NamespaceContext;
import javax.xml.parsers.*;
import javax.xml.xpath.*;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
public class Demo {
public static void main(String[] args) throws Exception {
String xml = "<soapenv:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ser=\"http://services.web.post.list.com\"><soapenv:Header><authInfo xsi:type=\"soap:authentication\" xmlns:soap=\"http://list.com/services/SoapRequestProcessor\"><!--You may enter the following 2 items in any order--><username xsi:type=\"xsd:string\">[email protected]</username><password xsi:type=\"xsd:string\">PfasdfRem91</password></authInfo></soapenv:Header></soapenv:Envelope>";
System.out.println(xml);
DocumentBuilderFactory domFactory = DocumentBuilderFactory
.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document doc = builder.parse(new InputSource(new StringReader(xml)));
XPath xpath = XPathFactory.newInstance().newXPath();
xpath.setNamespaceContext(new NamespaceContext() {
@Override
public Iterator getPrefixes(String arg0) {
return null;
}
@Override
public String getPrefix(String arg0) {
return null;
}
@Override
public String getNamespaceURI(String arg0) {
if("soapenv".equals(arg0)) {
return "http://schemas.xmlsoap.org/soap/envelope/";
}
return null;
}
});
// XPath Query for showing all nodes value
try {
XPathExpression expr = xpath
.compile("/soapenv:Envelope/soapenv:Header/authInfo/password");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
System.out.println("Got " + nodes.getLength() + " nodes");
// System.out.println(nodes.item(0).getNodeValue());
} catch (Exception E) {
System.out.println(E);
}
}
}
输出
<soapenv:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ser="http://services.web.post.list.com"><soapenv:Header><authInfo xsi:type="soap:authentication" xmlns:soap="http://list.com/services/SoapRequestProcessor"><!--You may enter the following 2 items in any order--><username xsi:type="xsd:string">[email protected]</username><password xsi:type="xsd:string">PfasdfRem91</password></authInfo></soapenv:Header></soapenv:Envelope>
Got 1 nodes
+1
谢谢,帮帮我 – Mufanu 2015-04-28 11:50:59
答
添加一些最新的答复.. 要获取特定节点的值可以使用below-- [System.out.println(nodes.item(0).getTextContent());
]
尝试这些: http://stackoverflow.com/questions/5673708/parsing-xml-with-xpath-in-java-get-data-from-xml-file-with-xpath-and-nodelist http://stackoverflow.com /疑问句tions/5519766/search-in-xml-file-with-xpath-in-android/5664438#5664438 – alibenmessaoud 2012-07-25 07:50:47
谢谢我会试试这些 – Raheel 2012-07-25 07:54:51