如何读取所有IP地址在一个文本文件，并遍历每个IP地址只有一次

Question

我上线re.search错误。

def search(pattern, string, flags=0): 
"""Scan through string looking for a match to the pattern, returning 
    a match object, or None if no match was found.""" 
return _compile(pattern, flags).search(string) 

---

代码：

def IP(): 
file = open('mbox.txt' , 'r') 
count = 0 
for line in file: 
    address = re.search(r"\b\d{1,3}\. \d{1,3}\. d{1,3}\. \d{1,3}\b", file) 
    for line in address: 
     ip = address 
     if line != allIPS: 
      ip.add(ip) 
      ip.add('\n') 
      count = count +1 
return (count) 

def main(): 
    #global statement for fhand 
    print("This program does the folowing: ") 
    print("The sum of lines in the file: %d " % (lineCount())) 
    print("The number of messages in the file: %d " % (MsgCount())) 
    print("All IP Addresses: %d\n " % (IP() )) 

if __name__ == '__main__': 
main() 

Answer 1

我看到一个错误 - 你需要line而不是file在re.search()

Answer 2

你的正则表达式中有多余的空间，将让你从匹配点IPv4地址和你如何尝试迭代线路有问题。试试这个：

def IP(): 
    # use a set to maintain unique addresses. no need to check if the 
    # address is in the set because duplicates are automatically removed 
    # during add. 
    allIPS = set() 

    # open with a context manager for automatic close. You dont need to 
    # specify the mode because "r" is the default. 
    with open('mbox.txt') as myfile: 

     # now iterate the lines 
     for line in myfile: 

      # use findall to find all matches in the line and 
      # update the set 
      allIPS.update(
       re.findall(r"\b\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\b", 
        line)) 

    # it seems like all you care about is the number of unique addresses 
    return len(allIPS)