如何将我的消息放在我想要的地方使用php
这是我的代码,我需要我的消息出现在窗体顶部,但出现错误。 我需要打印我的信息的地方,我把代码打印$ msg如何将我的消息放在我想要的地方使用php
关于这个请任何想法。
<form action="<?php $_SERVER['PHP_SELF']; ?>" method="post">
<table width="300" border="0">
<tr>
<td colspan="2"><?php print($msg); ?></td>
</tr>
<tr>
<td> *First name</td>
<td><span id="sprytextfield3">
<input type="text" value="" name="RFname" />
<br>
<span class="textfieldRequiredMsg">A value is required.</span></span></td>
</tr>
<tr>
<td>*Last name</td>
<td><span id="sprytextfield4">
<input type="text" value="" name="RLname" />
<br>
<span class="textfieldRequiredMsg">A value is required.</span></span></td>
</tr>
<tr>
<td>*User name</td>
<td><span id="sprytextfield1">
<input type="text" name="UserName" value="" />
<br />
<span class="textfieldRequiredMsg">A value is required.</span></span></td>
</tr>
<tr>
<td>*Password</td>
<td><span id="sprypassword1">
<input type="password" name="UserPass" value="" />
<span class="passwordRequiredMsg"><br />
A value is required.</span></span></td>
</tr>
<tr>
<td>*Email</td>
<td><span id="sprytextfield2">
<input type="text" name="UserEmail" value="" />
<br />
<span class="textfieldRequiredMsg">A value is required.</span><span class="textfieldInvalidFormatMsg">Invalid format.</span></span></td>
</tr>
<tr>
<td>Web site</td>
<td><input type="text" name="WebSite" value="" /></td>
</tr>
<tr>
<td> </td>
<td><input name="submited" type="submit" onClick="MM_swapImage('Image1','','images/blog.png',1)" value="Register"/></td>
</tr>
</table>
</form>
</div>
<div class="image_NewUserRegister"><iframe src="images/Untitled-2.jpg" name="now_regist" width="207" height="280" scrolling="no" frameborder="0"></iframe></div>
</div>
<?php
if(isset($_POST['submited'])) {
$RFname = $_POST['RFname'];
$RLname = $_POST['RLname'];
$USERname = $_POST['UserName'];
$USERpassword = $_POST['UserPass'];
$USERemail = $_POST['UserEmail'];
$USERwebsite = $_POST['WebSite'];
$check=$db->query("select 1 from loginaccess where Email ='".$USERemail."'");
if(mysqli_num_rows($check) > 0) {
$msg = "<span style='color:#F00; font-size:14px; font-weight:bold;'>This email already taken</span>";
}
这是我的代码,我需要我的消息出现在我的窗体的顶部,但我得到了一个错误。我需要打印我的信息的地方,我把代码打印$ msg
关于这个请任何想法。
您确实需要在之前设置消息,然后尝试输出它。
为了详细说明大卫的回答是:形式标记之前挪动了PHP块,像这样:
<?php
if(isset($_POST['submited'])) {
$RFname = $_POST['RFname'];
$RLname = $_POST['RLname'];
$USERname = $_POST['UserName'];
$USERpassword = $_POST['UserPass'];
$USERemail = $_POST['UserEmail'];
$USERwebsite = $_POST['WebSite'];
$check=$db->query("select 1 from loginaccess where Email ='".$USERemail."'");
if(mysqli_num_rows($check) > 0) {
$msg = "<span style='color:#F00; font-size:14px; font-weight:bold;'>This email already taken</span>";
}
?>
<form action="<?php $_SERVER['PHP_SELF']; ?>" method="post">
<table width="300" border="0">
<tr>
<td colspan="2"><?php print($msg); ?></td>
</tr>
<tr>
<td> *First name</td>
<td><span id="sprytextfield3">
<input type="text" value="" name="RFname" />
<br>
<span class="textfieldRequiredMsg">A value is required.</span></span></td>
</tr>
<tr>
<td>*Last name</td>
<td><span id="sprytextfield4">
<input type="text" value="" name="RLname" />
<br>
<span class="textfieldRequiredMsg">A value is required.</span></span></td>
</tr>
<tr>
<td>*User name</td>
<td><span id="sprytextfield1">
<input type="text" name="UserName" value="" />
<br />
<span class="textfieldRequiredMsg">A value is required.</span></span></td>
</tr>
<tr>
<td>*Password</td>
<td><span id="sprypassword1">
<input type="password" name="UserPass" value="" />
<span class="passwordRequiredMsg"><br />
A value is required.</span></span></td>
</tr>
<tr>
<td>*Email</td>
<td><span id="sprytextfield2">
<input type="text" name="UserEmail" value="" />
<br />
<span class="textfieldRequiredMsg">A value is required.</span><span class="textfieldInvalidFormatMsg">Invalid format.</span></span></td>
</tr>
<tr>
<td>Web site</td>
<td><input type="text" name="WebSite" value="" /></td>
</tr>
<tr>
<td> </td>
<td><input name="submited" type="submit" onClick="MM_swapImage('Image1','','images/blog.png',1)" value="Register"/></td>
</tr>
</table>
</form>
</div>
<div class="image_NewUserRegister"><iframe src="images/Untitled-2.jpg" name="now_regist" width="207" height="280" scrolling="no" frameborder="0"></iframe></div>
</div>
HTH。
感谢泰森T.但是没有任何其他方式可以解决这个问题,我肯定有一个方法 – 2011-12-20 22:20:43
还有其他方法,你可以改变'print($ msg);'在你的PHP代码中调用一个函数来生成消息。 – 2011-12-20 22:23:52
@Yousef不,没有。在脚本运行之前,变量不会被分配。这是纯粹的顺序编程。编辑:大卫有一点,但现在,我仍然认为答案是“不”。 – 2011-12-20 22:23:55
你能告诉我一个例子,请 – 2011-12-20 22:16:07
无聊的人,希望他们的马先于他们的车...:] – 2011-12-20 22:19:16
天向T.感谢重播,但我来这里是为了解决一些不傻反正我会尽力做你刚告诉我的事情,我需要时间来调整我的代码页中的每一件事,因为它很大谢谢亲爱的泰森T.对你而言很棒 – 2011-12-21 15:02:05