php返回包含文件的内容到javascript

Question

我正面临从PHP返回值到JSON的问题。

如果成功或失败的警报将与JavaScript文件内include '../core/init.php';的内容一起显示。但我只需要成功或失败的警报。请帮助

Requestfile：

$id = intval($_REQUEST['id']); 
$empid=$_REQUEST['empid']; 

include '../core/init.php'; 

if($user_data['empid']==$empid){ 
    $delete_sql = "delete from datatable where sl=$id"; 
    mysql_query($delete_sql); 
    echo json_encode("success"); 
    } 
    else{ 
    echo json_encode("failure"); 
} 

主页：

$.ajax({ 
url: 'returnpage.php', 
type: 'post', 
data: { 
'id' : row.sl, 
'empid':row.empid     
}, 
success:function(status){ 
alert(status); 
}, 
error:function(status){ 
alert(status); 
} 

---

警示窗口：

<style> 

/*html { 

    background: url(includes/background.jpg) no-repeat center center fixed; 

    -webkit-background-size: cover; 

    -moz-background-size: cover; 

    -o-background-size: cover; 

    background-size: cover; 

}*/ 

</style> 



<script type="text/javascript" src="css/js/browsercheck.js"></script> 

<script > 

var browser_name=browserinfo(); 

//alert(browser_name); 

if(browser_name!=="Firefox"){ 
    window.location="non_compatible_browser.php"; 
} 
</script> 



<script type="text/javascript" src="css/js/browsercheck.js"></script> 

<script > 

    // alert("Application Will be down..!!\nFrom 23-Jan-2016 07:15 PM to 23-Jan-2016 08:15 PM \nPlease save the data. ") 

    var browser_name=browserinfo(); 

    //alert(browser_name); 

    if(browser_name!=="Firefox"){ 

     window.location="non_compatible_browser.php"; 

    } 

    //window.location="Maintenance_page.php"; 

//exit(); 

</script> 

"failure" 

Answer 1

使用exit如下回应后：

$id = intval($_REQUEST['id']); 
    $empid=$_REQUEST['empid']; 

    include '../core/init.php'; 

    if($user_data['empid']==$empid){ 
     $delete_sql = "delete from datatable where sl=$id"; 
     mysql_query($delete_sql); 
     echo json_encode("success"); 
exit; 
     } 
     else{ 
     echo json_encode("failure"); 
exit; 
    } 

Answer 2

添加数据类型： 'JSON' 到您的AJAX JS代码：

$.ajax({ 
url: 'returnpage.php', 
type: 'post', 
dataType: 'JSON', 
data: { 
'id' : row.sl, 
'empid':row.empid     
}, 
success:function(status){ 
alert(status); 
}, 
error:function(status){ 
alert(status); 
} 

Answer 3

JavaScript的变化，确保您的文章参数的值

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script> 
<script> 
$(document).ready(function(){ 

    $.ajax({ 
     url: 'returnpage.php', 
     type: 'post', 
     data: { 
      'id' : row.sl, 
      'empid':row.empid     
     }, 
     dataType:'json', 
     success:function(result){ 
      alert(result.status); 
     }, 
     error:function(result){ 
      alert(result); 
     } 
    }); 
}); 
</script> 

PHP改变

<?php 

$id = intval($_REQUEST['id']); 
$empid=$_REQUEST['empid']; 

$data = array(); 
$data['status'] = 'failure'; 

//include '../core/init.php'; 

if($user_data['empid']==$empid){ 
    $delete_sql = "delete from datatable where sl=$id"; 
    $result = mysql_query($delete_sql); 

    if($result) { 
     $data['status'] = 'success'; 
    } 
} 
echo json_encode($data);