Ajax代码无响应
问题描述:
嗨,我有麻烦使这个Ajax代码与JavaScript的工作。该函数被称为studentReqHandler,带有一个按钮onclick函数,一切都在echo中。这是函数studentReqHandler的代码:Ajax代码无响应
echo "<script type='text/javascript'>
function studentReqHandler(action,id,email,elem){
_(elem).innerHTML = 'processing ...';
var ajax = ajaxObj('POST', 'verifying.php');
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText == 'accept_ok'){
_(elem).innerHTML = '<b>User Verified!</b><br />';
} else {
_(elem).innerHTML = ajax.responseText;
}
}
}
ajax.send('action='+action+'&id='+id+'&email='+email);
}
</script>
这是的onclick按钮:
<button onclick='studentReqHandler(\"accept\",\"".$id."\",\"".$email."\",\"user_info_".$id."\")'>accept</button> or
“;
其他Ajax相关的功能:
function ajaxObj(meth, url) {
var x = new XMLHttpRequest();
x.open(meth, url, true);
x.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
return x;
}
function ajaxReturn(x){
if(x.readyState == 4 && x.status == 200){
return true;
}
}
和持续的PHP的这个工作:
if (isset($_POST['action']) && isset($_POST['id'])&& isset($_POST['email'])){
$id = preg_replace('#[^0-9]#', '', $_POST['id']);
$email = $_POST['email'];
if($_POST['action'] == "accept"){
$sql = "UPDATE profile SET verified='1' WHERE id='$id' AND email='$email' LIMIT 1";
$query = mysqli_query($db_conx, $sql);
mysqli_close($db_conx);
echo "accept_ok";
exit();
}
}
谁能弄清楚为什么不工作?
答
我粘贴此代码,它的工作原理:
误差最小,是你有在<按钮有些凌乱报价> JavaScript字符串。
<?php
/* using this at the top to check what happens when it posts. */
if (isset($_POST['action']) && isset($_POST['id'])&& isset($_POST['email'])){
$id = preg_replace('#[^0-9]#', '', $_POST['id']);
$email = $_POST['email'];
if($_POST['action'] == "accept"){
/* I commented out the query, so you must make sure that works right */
$sql = "UPDATE profile SET verified='1' WHERE id='$id' AND email='$email' LIMIT 1";
//$query = mysqli_query($db_conx, $sql);
// mysqli_close($db_conx);
echo "accept_ok";
exit();
}
}
/* some default values. You need to make sure you get these from somewhere.*/
$id=3;
$email="[email protected]";
/* ELEMENT changes when I click the button */
echo "Div Element <div id='element'>ELEMENT</div> area<br><br>";
?>
<script type='text/javascript'>
function studentReqHandler(action,id,email,elem) {
/* I used the basic document element locator */
document.getElementById('element').innerHTML = 'processing ...';
/* I posted to itself this time. */
var ajax = ajaxObj('POST', 'ajax.php');
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText == 'accept_ok'){
document.getElementById('element').innerHTML = '<b>User Verified!</b><br />';
} else {
document.getElementById('element').innerHTML = ajax.responseText;
}
}
}
ajax.send('action='+action+'&id='+id+'&email='+email);
}
function ajaxObj(meth, url) {
var x = new XMLHttpRequest();
x.open(meth, url, true);
x.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
return x;
}
function ajaxReturn(x){
if(x.readyState == 4 && x.status == 200){
return true;
}
}
</script>
/* There were too many quotes and \'s in the original button. */
<br>The Button<br>
<?php
echo "<button onclick=\"studentReqHandler('accept','$id','$email','user_info_$id') \">accept</button>";
?>
始终消毒用户输入!! http://bobby-tables.com/php.html – edwardmp 2013-04-27 00:58:00
你使用的是萤火虫/开发者工具吗?什么不起作用? PHP返回错误?你有没有检查你的日志?你是否收到客户端错误? – dm03514 2013-04-27 01:02:35
一切,现在的情况是该元素的变化accept_ok。 php不会返回accept_ok – 2013-04-27 01:32:57