如何评价简单代数运算的难度

Question

我正在写一个简单的应用程序来帮助我的女儿练习基本代数（一年级）。例如，我想根据操作的难度给每个响应分配一个分数，其中2 + 2的值小于12-7。 您是否知道现有的算法可以查找并适应我的需求？

编辑

，如果你想看到的应用 https://algebro.herokuapp.com
• ，如果你想看到的代码https://gitlab.com/etozzato/algebro

**编辑← **

试图

使问题更具体;）

个

给出两个整数和一个基本的代数运算

算法输入：int a,b和string operation

算法输出：float difficulty

→有什么可以帮助推断难系数的因素是什么？

• 我一定会看看输入的数字，他们的距离可以是 在确定操作的复杂性很重要。 10 + 1显然比7 + 5更容易，因为（当不记忆并立即响应）需要更长的计数时间;
• 作为对前面陈述的修正，常见/简单的论点应该会降低操作的复杂度：0或10是一个很好的例子;

Answer 1

我不知道任何算法来找到一个方程的“困难”，但如果我有更多的时间，我可能会尝试玩弄像this ......即使它是阅读，这个概念可能适用于算术。

无论如何，这里是一个超级无聊后午夜裂缝的东西，可能与一些调整极其基本算术。你可以调整因素/重量，但这可能会让你开始。祝你好运！

function get_difficulty (eq) { 
    var difficulty = 0; 
    var settings = { 
     terms_factor : 3, //Multiply by the number of terms in an equation 
     digits_factor : 2, //Multiply by the number of digits in each term 
     negative_weight : 2, //Add this if subtracting two numbers in the equation yields a negative number 

     operations : { 
      "+" : 1, 
      "-" : 2, 
      "*" : 4, 
      "/" : 6, 

      "=" : 0 
     } 
    }; 

    eq += "="; 

    var ptr = 0; 
    var terms = 0; 
    var prev_term = null; 
    var len = eq.length; 
    var stack = [ ]; 

    var is_numeric = function (n) { 
     return /\d+/.test (n); //Not a brilliant way but works for basic arithmetic 
    }; 

    while (ptr < len) { 
     var tok = eq [ptr]; 

     if (tok !== " " && tok !== "(" && tok !== ")") { 
      if (is_numeric (tok)) { 
       stack.push (tok); 
      } else if (tok in settings.operations) { 
       var curr_term = parseInt (stack.join ("")); 
       if (prev_term !== null && curr_term > prev_term && ["-", "="].indexOf (tok) !== -1) { 
        difficulty += settings.negative_weight; 
       } 

       difficulty += stack.length * settings.digits_factor; 
       prev_term = curr_term; 
       stack = [ ]; 
       terms++; 

       difficulty += settings.operations [tok]; 
      } else { 
       console.log ("Unknown token: " + tok); 
      } 
     } 

     ptr++; 
    } 

    difficulty += terms * settings.terms_factor; 

    return difficulty; 
} 


console.log (get_difficulty (" 2 + 2 ")); //11 
console.log (get_difficulty (" 12 - 7 ")); //14 
console.log (get_difficulty (" 7 - 12 ")); //16 
console.log (get_difficulty (" 5 - 5 ")); //12 
console.log (get_difficulty (" 5 - 1205 ")); //20 
console.log (get_difficulty (" 5 - 1205 * 35 ")); //29 
console.log (get_difficulty (" 5 * 40 ")); //18 
console.log (get_difficulty (" 102 - 5/13 + 32 ")); //39 
console.log (get_difficulty (" 100 - 100 ")); //20 
console.log (get_difficulty (" 32 - 12 ")); //16 
console.log (get_difficulty (" 12 - 32 ")); //18