ANTLR 4.7 CharStreams.fromFileName(s)未找到
问题描述:
这是一个最小化的测试用例。它应该编译。注释掉的字符串是4.6版本,它可以编译和工作。所以我的构建环境似乎是正确的。ANTLR 4.7 CharStreams.fromFileName(s)未找到
import java.lang.*;
import java.util.*;
import java.io.*;
class xx {
public static void main(String[] args) {
try {
// org.antlr.v4.runtime.ANTLRInputStream input = new
// org.antlr.v4.runtime.ANTLRFileStream("file name here"); // compiles
org.antlr.v4.runtime.CharStream input = new
org.antlr.v4.runtime.CharStreams.fromFileName("file name here");
} catch (Exception e) {
e.printStackTrace();
}
}
}
$ javac xx.java
xx.java:8: error: cannot find symbol
org.antlr.v4.runtime.CharStream input = new org.antlr.v4.runtime.CharStreams.fromFileName("file name here");
^
symbol: class fromFileName
location: class CharStreams
1 error
我从ANTLR 4.6升级到4.7。其中一个变化是弃用ANTLRInputStream和ANTLRFileStream。那么,什么是(直接从采取的优秀和权威ANTLR 4参考):
import org.antlr.v4.runtime.*; // http://www.antlr.org/
import org.antlr.v4.runtime.tree.*;
String f ...
ANTLRInputStream input = new ANTLRFileStream(f);
现在是一样的东西:
CharStream input = new CharStreams.fromFileName(f);
我已经安装在/ usr/local/lib目录4.7 /我编译我的语法没有任何更改或错误。但是,当我编译生成的Java,我得到:
java -jar /usr/local/lib/antlr-4.7-complete.jar xx.g4
javac -Xlint:deprecation *.java
xxasm.java:61: error: cannot find symbol
CharStream input = new CharStreams.fromFileName(f);
^
symbol: class fromFileName
location: class CharStreams
1 error
我的类路径和Java版本是:
CLASSPATH=.:/usr/local/lib/antlr-4.7-complete.jar:/usr/local/lib/jopt-simple-5.0.3.jar:/usr/local/lib/junit-4.12-sources.jar:/usr/local/lib/gson-2.8.1.jar
javac -version
javac 1.8.0_131
OSX 10.12.5
任何想法?
...
public static org.antlr.v4.runtime.CharStream fromFileName(java.lang.String) throws java.io.IOException;
打开-verbose标志:在ANTLR-4.7-complete.jar与javap的期待时,一切都看起来不错
...
[loading ZipFileIndexFileObject[/usr/local/lib/antlr-4.7-complete.jar(org/antlr/v4/runtime/CharStreams.class)]]
dwasm.java:61: error: cannot find symbol
CharStream input = new CharStreams.fromFileName(f);
^
symbol: class fromFileName
location: class CharStreams
而且,不工作:
CharStream input = new org.antlr.v4.runtime.CharStreams.fromFileName(f);
org.antlr.v4.runtime.CharStream input = new
org.antlr.v4.runtime.CharStreams.fromFileName("file name goes here");
od -c
0004720 t i m e . C h a r S t r e a m s
0004740 . f r o m F i l e N a m e ( " f
0004760 i l e n a m e h e r e " ) ;
答
new CharStreams.fromFileName(f);
应该只是
CharStreams.fromFileName(f);
无论出于何种原因,当你犯这种错误的错误消息是可怕的。
谢谢!我知道它必须是简单的东西,我只是没有看到。再次,谢谢。 – Olsonist