Powershell有没有简单的方法将int 5转换为字符串5或68到68？

Question

我想弄清楚是否有一种简单的方法将数字转换为单词9并将其转换为9。

Answer 1

有一个很好的.NET库，名为Humanizer，可以做到这一点。我还没有尝试过，但它看起来像有一个PowerShell wrapper。我怀疑这将完全符合你的需要。

Answer 2

这已被问到关于.NET/C＃;你可以把它放在一个类中，并在powershell中使用Add-Type来完成这个工作。

.NET convert number to string representation (1 to one, 2 to two, etc...)

也许是这样的（未经测试）：

$class = @" 
    public class Num2Word 
    { 
     public static string NumberToText(int n) 
      { 
      if (n < 0) 
       return "Minus " + NumberToText(-n); 
      else if (n == 0) 
       return ""; 
      else if (n <= 19) 
       return new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", 
       "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", 
       "Seventeen", "Eighteen", "Nineteen"}[n-1] + " "; 
      else if (n <= 99) 
       return new string[] {"Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", 
       "Eighty", "Ninety"}[n/10 - 2] + " " + NumberToText(n % 10); 
      else if (n <= 199) 
       return "One Hundred " + NumberToText(n % 100); 
      else if (n <= 999) 
       return NumberToText(n/100) + "Hundreds " + NumberToText(n % 100); 
      else if (n <= 1999) 
       return "One Thousand " + NumberToText(n % 1000); 
      else if (n <= 999999) 
       return NumberToText(n/1000) + "Thousands " + NumberToText(n % 1000); 
      else if (n <= 1999999) 
       return "One Million " + NumberToText(n % 1000000); 
      else if (n <= 999999999) 
       return NumberToText(n/1000000) + "Millions " + NumberToText(n % 1000000); 
      else if (n <= 1999999999) 
       return "One Billion " + NumberToText(n % 1000000000); 
      else 
       return NumberToText(n/1000000000) + "Billions " + NumberToText(n % 1000000000); 
     } 
    } 
@" 

Add-Type -TypeDefinition $class 

[Num2Word]::NumberToText(555) 

没有理由你不能写为纯PowerShell的，但是这已经写！