如何从包含json数组的json对象在angularjs中获取特定值

问题描述：

我从mysql数据库中获取以下数据，其中“comment”来自一个表，“blog”是另一个表。现在我想通过ng-repeat在视图中显示这些数据。如何从包含json数组的json对象在angularjs中获取特定值

{ 
    "comment":[ 
    {"comment_id":"3","blog_id":"1","total_comment":"2"}, 
    {"comment_id":"9","blog_id":"8","total_comment":"3"} 
    ], 
    "blog":[ 
    {"id":"9","title":"jquery","description":"this is about jquery","date":"2016-08-27","status":"active"}, 
    {"id":"8","title":"javascript","description":"this is javascript post","date":"0000-00-00","status":"active"}, 
    {"id":"1","title":"angularjs","description":"this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.this blog is about angularjs.","date":"2016-07-12","status":"active"} 
    ] 
}

那么你尝试过什么？ – RiggsFolly

{{result.comment.total_comment}} and {{result.blog.title}}

–

我现在已经得到了回应的数据如何访问我需要的特定记录 –

答

如果相信“blog_id”是博客表和评论表之间的共同字段。

写联接查询在MySQL“ON blog.id = comment.blog_id”，让你得到你想要的数据，你可能会显示在响应NG-重复

如何从包含json数组的json对象在angularjs中获取特定值

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