Python lxml（objectify）：Xpath麻烦

Question

我试图解析XML文档，使用lxml objectify和xpath提取数据。下面是该文件的一个剪断：

<?xml version="1.0" encoding="UTF-8"?> 
<Assets> 
<asset name="Adham"> 
    <pos> 
    <x>27913.769923</x> 
    <y>5174.627773</y> 
    </pos> 
    <description>Ba bla bla</description> 
    <bar>(null)</bar> 
    </general> 
</asset> 
<asset name="Adrian"> 
    <pos> 
    <x>-179.477707</x> 
    <y>5286.959359</y> 
    </pos> 
    <commodities/> 
    <description>test test test</description> 
    <bar>more bla</bar> 
    </general> 
</asset> 
</Assets> 

我有以下方法：

def getALLattributesX(self, _root): 
    '''Uses getattributeX and parses through the attribute dict, assigning 
    values as it goes. _root is the main document root''' 
    for k in self.attrib: 
     self.getattributeX(_root, self.attribPaths[k], k) 

...调用该方法：

def getattributeX(self, node, x_path, _attrib): 
    '''Gets a value from an xml node indicated by an xpath 
    and assigns it to a the appropriate. If node does not exists 
    it assigns "error" 
    ''' 

    print node.xpath(x_path)[0].text 
    try: 
     self.attrib[_attrib] = node.xpath(x_path) 
    except KeyError: 
     self.misload = True 
    #except AttributeError: 
     # self.attrib[attrib] = "error loading " + attrib 
     #self.misload = True 

print语句是从测试。当我执行第一个方法时，它通过xml文档解析，成功停止每个资产对象。我必须为它找到的变量的字典，并为它使用路径免费字典，如下定义：

class tAssetList: 

    alist = {} #dict of assets 
    tlist = [] 
    tree = None # XML tree 
    root = None #root elem 

    def readXML(self, _filename): 
     #Load file 
     fileobject = open(_filename, "r") #read-only 
     self.tree = objectify.parse(fileobject) 
     self.root = self.tree.getroot() 

     for elem in self.root.asset: 
      temp_asset = tAsset() 
      a_name = elem.get("name") # get name, which is the key for dict 
      temp_asset.getALLattributesX(elem) 
      self.alist[a_name] = temp_asset 


class tAsset(obs.nxObject): 
    def __init__(self): 
     self.attrib = {"X_pos" : None, "Y_pos" : None} 
     self.attribPaths = {"X_pos" : '/pos/x', "Y_pos" : '/pos/y'} 

然而，XPath的似乎并不奏效时，我把它叫做节点上（这是一个客观的XML节点）。它只是输出[]，如果我直接将其等同，并且如果我尝试：[0] .text，它会给索引超出范围错误。

这是怎么回事？

Answer 1

/pos/x和/pos/y是绝对的XPath表达式，它们不选择任何元素，因为提供的XML文档没有pos顶层元素。

尝试：

pos/x 

和

pos/y