在列表视图中获取搜索数据的问题

Question

我已经在customadapter类中实现了可筛选，并且我能够通过listview进行搜索，但是当我清空搜索框时，我的列表仍显示最后一个搜索应用程序，而不是整个应用程序列表。

mainactivity.java

public class MainActivity extends ListActivity { 
List<ApplicationInfo> appList; 
ListAdapter listAdapter; 
PackageManager packageManager; 
Process suProcess; 
DataOutputStream os; 
ApplicationInfo info; 
EditText search; 
ArrayList<ApplicationInfo> applist; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 

    packageManager = getPackageManager(); 
    new LoadApplication().execute(); 

    search = (EditText) findViewById(R.id.searchView); 
    search.addTextChangedListener(new TextWatcher() { 
     @Override 
     public void beforeTextChanged(CharSequence s, int start, int count, int after) { 
     } 

     @Override 
     public void onTextChanged(CharSequence s, int start, int before, int count) { 
      listAdapter.getFilter().filter(s.toString()); 
     } 

     @Override 
     public void afterTextChanged(Editable s) { 

     } 
    }); 
} 
} 

我已经加入我的过滤器类。

private class ListFilter extends Filter { 
    @Override 
    protected FilterResults performFiltering(CharSequence constraint) { 
     FilterResults results = new FilterResults(); 
     if (constraint == null || constraint.length() == 0) { 
      results.values = applist; 
      results.count = applist.size(); 
     } else { 
      ArrayList<ApplicationInfo> info = new ArrayList<ApplicationInfo>(); 

      for (ApplicationInfo c : applist) { 
       if (c.loadLabel(packageManager).toString().toUpperCase().contains(constraint.toString().toUpperCase())) { 
        info.add(c); 
       } 
      } 
      results.values = info; 
      results.count = info.size(); 
     } 
     return results; 
    } 

    @Override 
    protected void publishResults(CharSequence constraint, FilterResults results) { 
     if (results.count == 0) { 
      notifyDataSetInvalidated(); 
     } else { 
      applist = (List<ApplicationInfo>) results.values; 
      notifyDataSetChanged(); 
     } 
    } 
} 

并覆盖了getFilter（）方法。

public Filter getFilter() { 

    if (filter == null) 
    { 
     filter=new ListFilter(); 
    } 
    return filter; 
} 

Answer 1

添加搜索您需要添加过滤器像下面的代码：

private class ItemFilter extends Filter { 
     @Override 
     protected FilterResults performFiltering(CharSequence constraint) { 

      String filterString = constraint.toString().toLowerCase(); 

      FilterResults results = new FilterResults(); 

      final List<String> list = originalData; 

      int count = list.size(); 
      final ArrayList<String> nlist = new ArrayList<String>(count); 

      String filterableString ; 

      for (int i = 0; i < count; i++) { 
       filterableString = list.get(i); 
       if (filterableString.toLowerCase().contains(filterString)) { 
        nlist.add(filterableString); 
       } 
      } 

      results.values = nlist; 
      results.count = nlist.size(); 

      return results; 
     } 

     @SuppressWarnings("unchecked") 
     @Override 
     protected void publishResults(CharSequence constraint, FilterResults results) { 
      filteredData = (ArrayList<String>) results.values; 
      notifyDataSetChanged(); 
     } 

    } 

按照以下链接，并在适配器中添加过滤器：

Filtering ListView with custom (object) adapter