HTTP状态500而不是HTTP状态的JAX-RS响应400

问题描述：

有时JAR-RS客户端发送错误的语法请求主体。服务器应回应HTTP status 400 (Bad Request)，但它回应HTTP status 500 (Internal Server Error)。HTTP状态500而不是HTTP状态的JAX-RS响应400

代码：

JAX-B模型类：

@XmlRootElement(namespace = "http://www.test.com/test") 
@XmlAccessorType(value = XmlAccessType.FIELD) 
public class TestModel { 

    @XmlElement 
    private String id; 
}

JAX-RS资源类：

@Path("test") 
public class TestResource { 

    @POST 
    @Consumes(MediaType.APPLICATION_JSON) 
    public void create(TestModel testModel) { 
     // some code 
    } 
}

CXF配置：

<jaxrs:server address="/rest" id="test" staticSubresourceResolution="true"> 
    <jaxrs:serviceBeans> 
     <ref bean="testResource" /> 
    </jaxrs:serviceBeans> 
    <jaxrs:providers> 
     <bean class="com.fasterxml.jackson.jaxrs.json.JacksonJaxbJsonProvider" /> 
    </jaxrs:providers> 
</jaxrs:server>

例子：

请求正文：

{"id2": "test"}

的id2是错误的，所以客户应该得到一个HTTP status 400，但它得到HTTP status 500。

服务器日志：

Caused by: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "id2" (class test.TestModel), not marked as ignorable (one known property: "id"]) 
    at [Source: [email protected]; line: 1, column: 10] (through reference chain: test.TestModel["id2"]) 
    at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:51) 
    at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:839) 
    at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1045) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1352) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1330) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:264) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:125) 
    at com.fasterxml.jackson.databind.ObjectReader._bind(ObjectReader.java:1470) 
    at com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:912) 
    at com.fasterxml.jackson.jaxrs.base.ProviderBase.readFrom(ProviderBase.java:811) 
    at org.apache.cxf.jaxrs.utils.JAXRSUtils.readFromMessageBodyReader(JAXRSUtils.java:1343) 
    at org.apache.cxf.jaxrs.utils.JAXRSUtils.readFromMessageBody(JAXRSUtils.java:1294) 
    at org.apache.cxf.jaxrs.utils.JAXRSUtils.processParameter(JAXRSUtils.java:826) 
    at org.apache.cxf.jaxrs.utils.JAXRSUtils.processParameters(JAXRSUtils.java:789) 
    at org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.processRequest(JAXRSInInterceptor.java:212) 
    ... 68 more

是否有配置杰克逊和/或CXF返回HTTP状态400错误的语法要求身体无schema validation或bean validation的方法吗？

答

问题是未映射到响应的异常（通过ExceptionMapper s）转换为一般服务器错误响应，因为运行时不知道如何处理异常。

jackson-jaxrs-provider模块有ExceptionMapper s来处理Jackson基本异常类JsonMappingException和JsonParseException。映射器分别为JsonMappingExceptionMapper和JsonParseExceptionMapper。这些映射器将异常映射到400响应以及作为响应主体的异常消息。如果你不喜欢这个响应体，你可以编写自己的映射器。

HTTP状态500而不是HTTP状态的JAX-RS响应400

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