如何使用Jaxb嵌套POJO类来生成Java中的XML模型
问题描述:
我正在使用JAXB创建一个xml数据模型,它似乎非常适合非复杂的XML模型,但只要我进入稍微复杂的XML,JAXB似乎并没有起作用。如何使用Jaxb嵌套POJO类来生成Java中的XML模型
这是XML代我想acheive:
<?xml version="1.0" encoding="UTF-8"?>
<SampleRoot xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="Sample.xsd">
<Name>Sample Name</Name>
<Description>This is a description</Description>
<Graph>Graph test</Graph>
<VerifyAttr>
<Data>id</Data>
<Value>32</Value>
</VerifyAttr>
<VeirfyXpath>
<MemXpath>/Root/Name</MemXpath>
<Value>Mosawi</Value>
</<VeirfyXpath>>
</SampleRoot>
这是嵌套POJO类,我创建了(我不应该创建一个嵌套的POJO或许他们分开了?):
package com.sample.model;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name="SampleRoot")
public class Sample {
private String name;
private String description;
private String graph;
public String getName() {
return name;
}
@XmlElement
public void setName(String name) {
this.name = name;
}
public String getDescription() {
return description;
}
@XmlElement
public void setDescription(String description) {
this.description = description;
}
public String getGraph() {
return graph;
}
@XmlElement
public void setGraph(String graph) {
this.graph = graph;
}
@XmlAccessorType(XmlAccessType.FIELD)
public class VerifyAttr {
private String data;
private String value;
public String getData() {
return data;
}
@XmlElement
public void setData(String data) {
this.data = data;
}
public String getValue() {
return value;
}
@XmlElement
public void setValue(String value) {
this.value = value;
}
}
@XmlAccessorType(XmlAccessType.FIELD)
public class VerifyXpath {
private String memXpath;
private String value;
public String getMemXpath() {
return memXpath;
}
@XmlElement
public void setMemXpath(String memXpath) {
this.memXpath = memXpath;
}
public String getValue() {
return value;
}
@XmlElement
public void setValue(String value) {
this.value = value;
}
}
}
这里是锻炼POJO模型演示:
public static void main(String[] args) {
Sample sample = new Sample();
sample.setName("Name");
sample.setDescription("This is a description");
sample.setGraph("Graph Test");
VerifyAttr va = sample.new VerifyAttr();
va.setData("id");
va.setValue("32");
VerifyXpath vx = sample.new VerifyXpath();
vx.setMemXpath("/Root/Name");
vx.setValue("Mosawi");
try {
JAXBContext jaxbContext = JAXBContext.newInstance(Sample.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(sample, new File("Sample.xml"));
jaxbMarshaller.marshal(sample, System.out);
} catch(Exception e) {
e.printStackTrace();
}
}
我的问题是,是t他没有生成上面定义的完整的XML。这是什么产生的:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<SampleRoot>
<description>This is a description</description>
<graph>Graph Test</graph>
<name>Name</name>
</SampleRoot>
我在做什么错?为什么我没有像上面那样获取模型XML?问题是与demo main
?
答
好吧,我可以通过阅读一些JaxB文档来了解这一点。我已经分离了的POJO分为3类,并调整了JAXB注释:
Sample.java
VerifyAttr.java
VerifyXpath.java
VerifyAttr.java
@XmlRootElement
@XmlAccessorType(XmlAccessType.PROPERTY)
@XmlType(propOrder={"dataAttr","valueAttr"})
public class VerifyAttr {
//...
}
VerifyXpath.java
@XmlRootElement
@XmlAccessorType(XmlAccessType.PROPERTY)
@XmlType(propOrder={"dataXpath","valueXpath"})
public class VerifyAttr {
//...
}
和根节点顶级:
Sample.java
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class VerifyAttr {
@XmlElement(name="VerifyAttr", type=VerifyAttr.class)
private ArrayList<VerifyAttr> va;
@XmlElement(name="VerifyXpath", type=VerifyXpath.class)
private ArrayList<VerifyXpath> vx;
// some other fields
//..getter and setters
}
希望这可以帮助其他人新JAXB