如何将UITapGestureRecognizer添加到表格视图单元格内的UILabel中？

Question

我正在使用NIB文件来布置自定义表格视图单元格。这个单元格带有一个名为lblName的标签。将UITapGestureRecognizer添加到此标签永远不会触发关联的事件。我有userInteractionEnabled = YES。

我猜测问题是UILabel在TableView中，并且表格/单元格视图正在拦截水龙头。我能做些什么吗？

我想要做的就是在按下UILabel时执行一些自定义操作！我所见过的所有解决方案都很荒谬。使用标准工具集应该很容易。但显然不是。

下面是我使用的代码：

- (void)tapAction { 
    NSLog(@"Tap action"); 
} 

- (void)viewDidLoad 
{ 
    [super viewDidLoad]; 
    // Do any additional setup after loading the view from its nib 

    UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
    [recognizer setNumberOfTapsRequired:1]; 
    //lblName.userInteractionEnabled = true; (setting this in Interface Builder) 
    [lblName addGestureRecognizer:recognizer]; 
} 

Answer 1

EASY WAY创建的UILabel ：

您也可以使用隐形b utton在该标签的顶部。所以它会减少您为该标签添加tapGesture的工作。

另一种方式：

你不应该为UILabel创建一个IBOutlet。当你这样做时，你会在自定义类实现文件中添加一个插座。您无法在其他文件中访问。因此，在自定义类IB中为该标签设置标签，并在cellForRowAtIndexPath:方法中编写代码。

更新：

在cellForRowAtIndexPath:方法，

for(UIView *view in cell.contentViews.subviews) { 
    if(view.tag == 1) { 
     UITapGestureRecognizer *tap=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
     [tap setNumberOfTapsRequired:1]; 
     [view addGestureRecognizer:tap]; 
    } 
} 

Answer 2

这样做的工作没有问题：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    ... 
    // create you cell 
    UILabel *lbl = [[UILabel alloc] initWithFrame:CGRectMake(0, 0, 100, 50)]; 
    [lbl setText:@"example"]; 
    [lbl setUserInteractionEnabled:YES]; 
    [cell.contentView addSubview:lbl]; 
    UITapGestureRecognizer *tap=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction:)]; 
    tap.tag = [NSIndexPath row]; 
    [tap setNumberOfTapsRequired:1]; 
    [lbl addGestureRecognizer:tap]; 
    ... 
} 

- (void)tapAction:(id)sender { 
    switch(((UITapGestureRecognizer *)sender).view.tag) { 
    case 0: 
      // code 
      break; 
    case 1: 
     // code 
     break; 
     .... 
    } 
} 

即使在情况下，与IB

Answer 3

方式的Dinesh建议的for循环使用属性变量而不将工作。

UITapGestureRecognizer *tap=[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
[tap setNumberOfTapsRequired:1]; 
[self.myUILabel addGestureRecognizer:tap]; 

Answer 4

UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapAction)]; 
[recognizer setNumberOfTapsRequired:1]; 
lblName.userInteractionEnabled = YES; 
[lblName addGestureRecognizer:recognizer]; 

Answer 5

一旦指定点击手势到的UILabel和用户交互设置为启用，在你的回调函数，你可以你可以添加在你的细胞的-awakeFromNib方法

UITapGestureRecognizer* gesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapGestureRecognizerAction:)]; 
[self.yourLabel setUserInteractionEnabled:YES]; 
[self.yourLabel addGestureRecognizer:gesture]; 

Answer 6

下一个从单元格视图中查找索引路径，但在超级视图中搜索：

- (UITableViewCell *) findCellInSuperview:(UIView *)view 
{ 
UITableViewCell *cell = nil; 

    NSString *className = NSStringFromClass([[view superview] class]); 
    if ([className isEqualToString:@"UITableViewCell"]) { 
     cell = (UITableViewCell *)[view superview]; 
    } else { 
     if ([view superview] != nil) { 
      cell = [self findCellInSuperview:[view superview]]; 
     } 
    } 

return cell; 
} 

Answer 7

对于Swift ， 你可以在你的cellForRowAtIndexPath方法中添加这个。

var tap = UITapGestureRecognizer(target: self, action: "labelTapped") 
tap.numberOfTapsRequired = 1 
cell.label.addGestureRecognizer(tap) 
cell.label.tag = indexPath.row 

然后，对于动作

func labelTapped(gesture: UITapGestureRecognizer) { 
    let indexPath = NSIndexPath(forRow: gesture.view!.tag, inSection: 0) 
    let cell = tableView.cellForRowAtIndexPath(indexPath) as UITableViewCell 

    // Do whatever you want. 
} 

Answer 8

可以使用以下代码来对UILable添加敲击手势中的UITableView细胞

UITapGestureRecognizer *lblAction = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(lblClick:)]; 
lblAction.delegate =self; 
lblAction.numberOfTapsRequired = 1; 
cell.lbl.userInteractionEnabled = YES; 
[cell.lbl addGestureRecognizer:lblAction]; 

和访问选择方法

- (void)lblClick:(UITapGestureRecognizer *)tapGesture { 
    UILabel *label = (UILabel *)tapGesture.view; 
    NSLog(@"Lable tag is ::%ld",(long)label.tag); 
} 

对于斯威夫特

let tapGesture : UITapGestureRecognizer = UITapGestureRecognizer.init(target: self, action: #selector(lblClick(tapGesture:))) 
tapGesture.delegate = self 
tapGesture.numberOfTapsRequired = 1 
cell.lbl.userInteractionEnabled = true 
cell.lbl.tag = indexPath.row 
cell.lbl.addGestureRecognizer(tapGesture) 

func lblClick(tapGesture:UITapGestureRecognizer){ 
    print("Lable tag is:\(tapGesture.view!.tag)") 
} 

Answer 9

对于斯威夫特3

let tapGesture : UITapGestureRecognizer = UITapGestureRecognizer.init(target: self, action: 
#selector(lblClick(tapGesture:))) 
tapGesture.delegate = self 
tapGesture.numberOfTapsRequired = 1 
cell.lbl.isUserInteractionEnabled = true 
cell.lbl.tag = indexPath.row 
cell.lbl.addGestureRecognizer(tapGesture) 

然后

func lblClick(tapGesture:UITapGestureRecognizer){ 
    print("Lable tag is:\(tapGesture.view!.tag)") 
}