如何获得来自多个用户的输入
问题描述:
这是一个3人游戏。在这个游戏中,1到99之间的秘密数字是随机生成的。每个玩家轮流猜测这个秘密号码。玩家将被告知他的猜测是高于还是低于随机生成的数字。当其中一名玩家猜对时,游戏将结束。 出局将显示每个球员的猜测数量和胜利者。如何获得来自多个用户的输入
我已经输入了一些代码:
import random
userNumber = input("enter a number between 1 and 99:")
secretNummber = random.randint(1,99)
if userNumber > secretNumber:
print "too high..."
elif userNumber < secretNumber:
print "too low..."
else:
print "you made the right guess..."
print "secret number"+str(secretNumber)
答
你可以做的是使用一个循环为每个猜测的“圆”,然后坐3个输入每轮:
import random
secretNumber = random.randint(1,99)
while True:
for player in range(1,4):
userNumber = input("Player %s: enter a number between 1 and 99:" % player)
if userNumber > secretNumber:
print "too high..."
elif userNumber < secretNumber:
print "too low..."
else:
print "Player %s, you made the right guess..." % player
exit(0)
答
import random
from itertools import cycle
secretNumber = random.randint(1,99)
for player in cycle(["Tom", "Dick", "Harry"]):
userNumber = int(raw_input("{}: enter a number between 1 and 99:".format(player)))
if userNumber > secretNumber:
print "too high..."
elif userNumber < secretNumber:
print "too low..."
else:
print "{}, you made the right guess...".format(player)
break
+0
有没有一种方法来计算猜测的数量 –
+0
你可以使用'for guess_number,枚举中的玩家(cycle([“Tom”,“Dick”,“Harry”]),1):' –
这是什么问题? – Serial
每个猜测都会产生一个新号码。 – andrewb