替换字符串不行

Question

我需要 “ID =” 之后添加字符串@ “d”

示例=

url = @"id=63488320543140151742289377" 

需求是

url = @"id=d63488320543140151742289377" 

我已经试过这样：

NSRange range = [url rangeOfString:@"id="]; 
[url stringByReplacingCharactersInRange:range withString:@"id=d"]; 

但不工作

Answer 1

url = [url stringByReplacingOccurrencesOfString:@"id=" withString:@"id=d"]; 

Answer 2

stringByReplacingCharactersInRange返回一个字符串。如果您将新字符串分配给某个变量（例如url = [url stringByReplacingCharactersInRange:range withString:@"id=d"];）