pyqt4按钮点击处理程序
我有一个问题使用pyqt4: 这里是我正在使用的代码,重点是,如果在pushOk按钮的事件处理程序中点击我呼叫chiedi_numeri()它不会显示我任何形式,而如果我调用chiedi_numeri()它说,参数3和QObjectConnect具有无效类型。我该如何解决它? 感谢pyqt4按钮点击处理程序
class Ui_dialog(object):
def setupUi(self, dialog):
dialog.setObjectName("dialog")
dialog.resize(400, 300)
self.pushOk = QtGui.QPushButton(dialog)
self.pushOk.setGeometry(QtCore.QRect(200, 150, 75, 23))
self.pushOk.setObjectName("pushOk")
self.radioButton = QtGui.QRadioButton(dialog)
self.radioButton.setEnabled(True)
self.radioButton.setGeometry(QtCore.QRect(60, 40, 261, 18))
self.radioButton.setChecked(True)
self.radioButton.setObjectName("radioButton")
self.radioButton_2 = QtGui.QRadioButton(dialog)
self.radioButton_2.setGeometry(QtCore.QRect(60, 70, 281, 18))
self.radioButton_2.setObjectName("radioButton_2")
self.radioButton_3 = QtGui.QRadioButton(dialog)
self.radioButton_3.setGeometry(QtCore.QRect(60, 100, 281, 18))
self.radioButton_3.setObjectName("radioButton_3")
self.labelRisultato = QtGui.QLabel(dialog)
self.labelRisultato.setGeometry(QtCore.QRect(70, 200, 261, 51))
self.labelRisultato.setObjectName("labelRisultato")
self.retranslateUi(dialog)
QtCore.QMetaObject.connectSlotsByName(dialog)
def retranslateUi(self, dialog):
dialog.setWindowTitle(QtGui.QApplication.translate("dialog", "Fibonacci", None, QtGui.QApplication.UnicodeUTF8))
self.pushOk.setText(QtGui.QApplication.translate("dialog", "Ok", None, QtGui.QApplication.UnicodeUTF8))
self.radioButton.setText(QtGui.QApplication.translate("dialog", "Calcola la serie di Fibonacci", None, QtGui.QApplication.UnicodeUTF8))
self.radioButton_2.setText(QtGui.QApplication.translate("dialog", "Calcola la serie di Fibonacci in un intervallo", None, QtGui.QApplication.UnicodeUTF8))
self.radioButton_3.setText(QtGui.QApplication.translate("dialog", "Calcola l\'ennesimo elemento della serie di Fibonacci", None, QtGui.QApplication.UnicodeUTF8))
def fibonacci():
a , b = 0, 1
while 1:
a, b = b, a + b
yield a
def chiedi_numeri():
try:
max_ = int(raw_input("Inserisci un numero: "))
if max_ <= 0 :
print "Il numero", max_, "non e' positivo!"
else:
start = 0
for i in fibonacci():
if start > max_:
break
else:
start += 1
if start == max_:
print "Il", max_, "numero della sequenza di Fibonacci e'", i
except ValueError:
print "Non hai inserito un numero!"
if __name__ == "__main__":
import sys
app = QtGui.QApplication(sys.argv)
dialog = QtGui.QDialog()
ui = Ui_dialog()
ui.setupUi(dialog)
app.connect(ui.pushOk, Qt.SIGNAL("clicked()"), chiedi_numeri())
dialog.show()
sys.exit(app.exec_())
当把信号连接到一个Python函数,传递函数对象。换句话说,由于您传递的函数没有调用它,因此您会省略后面的括号。试着改变上面一行改为app.connect(ui.pushOk, Qt.SIGNAL("clicked()"), chiedi_numeri)
有一件事你做错了,是在这一行:
app.connect(ui.pushOk, Qt.SIGNAL("clicked()"), chiedi_numeri())
希望此功能按钮被按下时运行,而不是当连接而成。为此,请在chiedi_numeri
后删除括号:
app.connect(ui.pushOk, Qt.SIGNAL("clicked()"), chiedi_numeri)
然后,应该正确连接按钮。
不过,我不知道你下面的意思:
I call chiedi_numeri() it does not show me any form
你是什么意思的“形式”呢?你是否期待另一个窗口弹出并询问一个号码?目前,您的程序要求您在启动应用程序的终端/外壳/控制台窗口中输入一个数字。
从PyQt4的进口QtCore,QtGui 从PyQt4.QtCore进口* 从PyQt4.QtGui进口*
尝试: _fromUtf8 = QtCore.QString.fromUtf8 除AttributeError的: _fromUtf8 =拉姆达S:小号
类Ui_Dialog(对象): DEF setupUi(个体,对话): dialog.setObjectName(_fromUtf8( “对话”)) dialog.resize(600,400) self.pushOk = QtGui.QPushButton(对话) self.pushOk.setGeometry(QtCore.QRect(200,150,75,23)) self.pushOk.setObjectName( “pushOk”)
self.radioButton = QtGui.QRadioButton(dialog)
self.radioButton.setEnabled(True)
self.radioButton.setGeometry(QtCore.QRect(60, 40, 261, 18))
self.radioButton.setChecked(True)
self.radioButton.setObjectName("radioButton")
self.radioButton_2 = QtGui.QRadioButton(dialog)
self.radioButton_2.setGeometry(QtCore.QRect(60, 70, 281, 18))
self.radioButton_2.setObjectName("radioButton_2")
self.radioButton_3 = QtGui.QRadioButton(dialog)
self.radioButton_3.setGeometry(QtCore.QRect(60, 100, 281, 18))
self.radioButton_3.setObjectName("radioButton_3")
self.labelRisultato = QtGui.QLabel(dialog)
self.labelRisultato.setGeometry(QtCore.QRect(70, 200, 261, 51))
self.labelRisultato.setObjectName("labelRisultato")
self.lineEdit = QtGui.QLineEdit(dialog)
self.lineEdit.setGeometry(QtCore.QRect(240, 39, 150, 18))
self.lineEdit.setStyleSheet(_fromUtf8("background-color: rgb(255, 255, 248);"))
self.lineEdit.setAlignment(QtCore.Qt.AlignRight|QtCore.Qt.AlignTrailing|QtCore.Qt.AlignVCenter)
self.lineEdit.setObjectName(_fromUtf8("lineEdit"))
self.textEdit = QtGui.QTextEdit(dialog)
self.textEdit.setGeometry(QtCore.QRect(10, 220, 250, 150))
self.textEdit.setStyleSheet(_fromUtf8("background-color: rgb(220, 220, 220);font: 17pt \"Adobe Courier\";"))
self.textEdit.setObjectName(_fromUtf8("textEdit"))
self.retranslateUi(dialog)
QtCore.QMetaObject.connectSlotsByName(dialog)
def retranslateUi(self, dialog):
dialog.setWindowTitle(QtGui.QApplication.translate("dialog", "Fibonacci", None, QtGui.QApplication.UnicodeUTF8))
self.pushOk.setText(QtGui.QApplication.translate("dialog", "Ok", None, QtGui.QApplication.UnicodeUTF8))
self.radioButton.setText(QtGui.QApplication.translate("dialog", "Calcola la serie di Fibonacci", None, QtGui.QApplication.UnicodeUTF8))
self.radioButton_2.setText(QtGui.QApplication.translate("dialog", "Calcola la serie di Fibonacci in un intervallo", None, QtGui.QApplication.UnicodeUTF8))
self.radioButton_3.setText(QtGui.QApplication.translate("dialog", "Calcola l\'ennesimo elemento della serie di Fibonacci", None, QtGui.QApplication.UnicodeUTF8))
类StaxQT4(QtGui.QDialog): DEF 初始化(个体):
QtGui.QDialog.__init__(self)
self.ui = Ui_Dialog()
self.ui.setupUi(self)
self.connect(self.ui.pushOk, QtCore.SIGNAL("clicked()"), self.chiedi_numeri)
DEF斐波纳契(个体):
A,b = 0,1
而1:
A,b = b,A + b
得到
DEF chiedi_numeri(个体): 尝试: MAX_ = INT(self.ui.lineEdit.text()) 如果MAX_ < = 0: self.ui.lineEdit.setText(“IL NUMERO %s non e'positivo!“%str(max_)) else: start = 0
对于我自己。斐波纳契():
如果开始> MAX_: 断裂 否则: 启动+ = 1 如果开始== MAX_: self.ui.textEdit.setText( “IL%S NUMERO德拉SEQUENZA二斐波E'” % STR(MAX_)) self.ui.textEdit.append(STR(I)) 除了ValueError异常: self.ui.lineEdit.settext()
如果名 = “非海inserito未NUMERO!” =“main”: import sys app = QtGui.QApplication(sys。 ARGV)
myapp = StaxQT4()
myapp.show()
sys.exit(app.exec_())
嗯,这个复制粘贴并未真正发挥作用,基本上你要分开的界面设置类Ui_Dialog和应用程序类 StaxQT4,也给其他的评论是正确的 看到这一行: 自我。连接(self.ui.pushOk,QtCore.SIGNAL(“clicked()”),self.chiedi_numeri) – dero 2011-05-28 14:04:27