扁平化JSON当密钥,只知道在运行时
问题描述:
比方说,我们有一个JSON结构如下内容(在火力地堡的实时数据库常用):扁平化JSON当密钥,只知道在运行时
{
"18348b9b-9a49-4e04-ac35-37e38a8db1e2": {
"isActive": false,
"age": 29,
"company": "BALOOBA"
},
"20aca96e-663a-493c-8e9b-cb7b8272f817": {
"isActive": false,
"age": 39,
"company": "QUONATA"
},
"bd0c389b-2736-481a-9cf0-170600d36b6d": {
"isActive": false,
"age": 35,
"company": "EARTHMARK"
}
}
预期的解决方案:
使用Decodable
我会喜欢将其转换成3个元素的数组:
struct BoringEntity: Decodable {
let id: String
let isActive: Bool
let age: Int
let company: String
init(from decoder: Decoder) throws {
// ...
}
}
let entities: [BoringEntity] = try! JSONDecoder()...
的ID属性对应于JSON对象的RO字符串,例如:18348b9b-9a49-4e04-ac35-37e38a8db1e2
。
解决方法:
我已经尝试过多种方法,但无需辅助实体(或者使用选配)不能得到id属性:
/// Incomplete BoringEntity version to make Decodable conformance possible.
struct BoringEntityIncomplete: Decodable {
let isActive: Bool
let age: Int
let company: String
}
// Decode to aux struct
let decoded = try! JSONDecoder().decode([String : BoringEntityIncomplete].self, for: jsonData)
// Map aux entities to BoringEntity
let entities = decoded.map { BoringEntity(...) }
使用init(from: Decoder)
并不像小事在其他情况下,由于密钥未知,因此不能使用keyedContainer(,)
。
是Decodable
不适合这些类型的案件?前
答
基础机构:
struct BoringEntity: Decodable {
let id: String
let isActive: Bool
let age: Int
let company: String
}
解决方法1:使用一个额外的结构没有密钥
/// Incomplete BoringEntity version to make Decodable conformance possible.
private struct BoringEntityBare: Decodable {
let isActive: Bool
let age: Int
let company: String
}
// Decode to aux struct
private let decoded = try! JSONDecoder().decode([String : BoringEntityBare].self, from: jsonData)
// Map aux entities to BoringEntity
let entities = decoded.map { BoringEntity(id: $0.key, isActive: $0.value.isActive, age: $0.value.age, company: $0.value.company) }
print(entities)
解决方案2:使用包装
由于代码的不同我能我的方法与他PhantomKeys
想法结合起来,但没有绕过它:必须始终使用一个额外的实体。
struct BoringEntities: Decodable {
var entities = [BoringEntity]()
// This really is just a stand-in to make the compiler happy.
// It doesn't actually do anything.
private struct PhantomKeys: CodingKey {
var intValue: Int?
var stringValue: String
init?(intValue: Int) { self.intValue = intValue; self.stringValue = "\(intValue)" }
init?(stringValue: String) { self.stringValue = stringValue }
}
private enum BareKeys: String, CodingKey {
case isActive, age, company
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: PhantomKeys.self)
// There's only one key
for key in container.allKeys {
let aux = try container.nestedContainer(keyedBy: BareKeys.self, forKey: key)
let age = try aux.decode(Int.self, forKey: .age)
let company = try aux.decode(String.self, forKey: .company)
let isActive = try aux.decode(Bool.self, forKey: .isActive)
let entity = BoringEntity(id: key.stringValue, isActive: isActive, age: age, company: company)
entities.append(entity)
}
}
}
let entities = try JSONDecoder().decode(BoringEntities.self, from: jsonData).entities
print(entities)
答
一对夫妇的事情,我回答你的问题:
1:注释(// id
)使JSON无效。 JSON不允许评论。
2:id
BoringEntity
属性来自哪里?
struct BoringEntity: Decodable {
let id: String // where is it stored in the JSON???
let isActive: Bool
let age: Int
let company: String
}
如果我忽略了这些东西,你可以在一个结构(BoringEntities
)包裹的BoringEntity
阵列。直接使用[BoringEntity]
并不可取,因为您必须掩盖Array
的默认init(from decoder:)
。
这里的技巧是让JSONDecoder
通过container.allKeys
财产给你回的密钥列表:
struct BoringEntity: Decodable {
let isActive: Bool
let age: Int
let company: String
}
struct BoringEntities: Decodable {
var entities = [BoringEntity]()
// This really is just a stand-in to make the compiler happy.
// It doesn't actually do anything.
private struct PhantomKeys: CodingKey {
var intValue: Int?
var stringValue: String
init?(intValue: Int) { self.intValue = intValue; self.stringValue = "\(intValue)" }
init?(stringValue: String) { self.stringValue = stringValue }
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: PhantomKeys.self)
for key in container.allKeys {
let entity = try container.decode(BoringEntity.self, forKey: key)
entities.append(entity)
}
}
}
用法:
let jsonData = """
{
"18348b9b-9a49-4e04-ac35-37e38a8db1e2": {
"isActive": false,
"age": 29,
"company": "BALOOBA"
},
"20aca96e-663a-493c-8e9b-cb7b8272f817": {
"isActive": false,
"age": 39,
"company": "QUONATA"
},
"bd0c389b-2736-481a-9cf0-170600d36b6d": {
"isActive": false,
"age": 35,
"company": "EARTHMARK"
}
}
""".data(using: .utf8)!
let entities = try JSONDecoder().decode(BoringEntities.self, from: jsonData).entities
我后来添加的注释来解释其中的id属性是从哪来的,明知它将使JSON无效 – nathan
所以'id'是,例如。 '18348b9b-9a49-4e04-ac35-37e38a8db1e2'? –
确实。我会编辑我的问题,以清除而不使json示例失效 – nathan